#include <bits/stdc++.h> using namespace std; #define FOR(i, l, r) for(int i = (l); i <= (r); ++i) #define REP(i, n) FOR(i, 0, (n) - 1) #define rep(i, a, b) for(int i = a; i < (b); ++i) #define all(x) x.begin(), x.end() #define sz(x) (int)(x).size() #define ssize(x) int(x.size()) #define pb push_back #define fi first #define se second #define ld long double typedef long long ll; typedef vector<int> vi; typedef pair<int, int> pii; typedef pair <ld, ld> pd; using LL=long long; #ifdef DEBUG auto &operator<<(auto &o, pair<auto, auto> p) { return o << "()" << p.first << ", " << p.second <<")"; } auto operator<<(auto &o, auto x)-> decltype(x.end(), o) { o << "{";int i = 0; for(auto e : x) o << ", "+!i++<<e; return o <<"}"; } #define debug(x...) cerr << "["#x"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(x) #else #define debug(...) {} #endif void solve() { int N; cin >> N; vector<int> a(N); REP(i, N) cin >> a[i]; sort(all(a)); vector<pii> comb; int cnt = 1; for (int i = 1; i < N; i++) { if (a[i] != a[i - 1]) { comb.pb({a[i-1], cnt}); cnt = 1; } else { cnt++; } } comb.pb({a[N-1], cnt}); sort(all(comb), [&] (auto x, auto y) { return x.se < y.se; }); int ans = 1; int i = 0, j = comb.size() - 1; while (i < j) { int ile = comb[j].se - 1; // Zostaly nam juz tylko pojedyncze grupy ans += (ile == 0); while (i < j && ile > 0) { // ile jeszcze mozemy dobrac int how_much = min(ile, comb[i].se); comb[i].se -= how_much; ile -= how_much; // jezeli wyczerpalismy to idziemy dalej if (comb[i].se == 0) i++; // jezeli nie mozemy dobierac i nie nie skonczyly // nam sie jeszcze grupy to zwieksz wynik if (ile == 0 && i != j) ans++; } j--; } cout << ans << '\n'; } signed main() { cin.tie(0)->sync_with_stdio(0); int t = 1; // cin >> t; while(t--) { solve(); } }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 | #include <bits/stdc++.h> using namespace std; #define FOR(i, l, r) for(int i = (l); i <= (r); ++i) #define REP(i, n) FOR(i, 0, (n) - 1) #define rep(i, a, b) for(int i = a; i < (b); ++i) #define all(x) x.begin(), x.end() #define sz(x) (int)(x).size() #define ssize(x) int(x.size()) #define pb push_back #define fi first #define se second #define ld long double typedef long long ll; typedef vector<int> vi; typedef pair<int, int> pii; typedef pair <ld, ld> pd; using LL=long long; #ifdef DEBUG auto &operator<<(auto &o, pair<auto, auto> p) { return o << "()" << p.first << ", " << p.second <<")"; } auto operator<<(auto &o, auto x)-> decltype(x.end(), o) { o << "{";int i = 0; for(auto e : x) o << ", "+!i++<<e; return o <<"}"; } #define debug(x...) cerr << "["#x"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(x) #else #define debug(...) {} #endif void solve() { int N; cin >> N; vector<int> a(N); REP(i, N) cin >> a[i]; sort(all(a)); vector<pii> comb; int cnt = 1; for (int i = 1; i < N; i++) { if (a[i] != a[i - 1]) { comb.pb({a[i-1], cnt}); cnt = 1; } else { cnt++; } } comb.pb({a[N-1], cnt}); sort(all(comb), [&] (auto x, auto y) { return x.se < y.se; }); int ans = 1; int i = 0, j = comb.size() - 1; while (i < j) { int ile = comb[j].se - 1; // Zostaly nam juz tylko pojedyncze grupy ans += (ile == 0); while (i < j && ile > 0) { // ile jeszcze mozemy dobrac int how_much = min(ile, comb[i].se); comb[i].se -= how_much; ile -= how_much; // jezeli wyczerpalismy to idziemy dalej if (comb[i].se == 0) i++; // jezeli nie mozemy dobierac i nie nie skonczyly // nam sie jeszcze grupy to zwieksz wynik if (ile == 0 && i != j) ans++; } j--; } cout << ans << '\n'; } signed main() { cin.tie(0)->sync_with_stdio(0); int t = 1; // cin >> t; while(t--) { solve(); } } |