#pragma GCC optimize("O3") #include <bits/stdc++.h> #define fi first #define se second #define pn printf("\n") #define ssize(x) int(x.size()) #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() #define bitcount(x) __builtin_popcount(x) #define clz(x) __builtin_clz(x) #define ctz(x) __builtin_ctz(x) using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<int, ll> pil; typedef pair<ll, int> pli; typedef pair<ll, ll> pll; typedef double db; typedef long double ldb; #define vv vector /*void read(int &a){ char c = getchar_unlocked(); a = 0; while(c<'0' || '9'<c) c = getchar_unlocked(); while('0'<=c&&c<='9') a = (a<<3)+(a<<1)+c-'0', c = getchar_unlocked(); }*/ int inf = 2e09; ll infll = 2e18; int mod = (1<<23)*119+1; int add(int a, int b){return a+b >= mod ? a+b - mod : a+b;} int sub(int a, int b){return a-b < 0 ? a-b + mod : a-b;} int mul(int a, int b){return int(a * ll(b) % mod);} int fpow(int a, int b){ int ret = 1; while(b){ if(b & 1) ret = mul(ret, a); b >>= 1, a = mul(a, a); } return ret; } int inv(int a){ return fpow(a, mod-2); } int coeff(int n, int k, vector<int> &fac, vector<int> &invfac){ if(n < k) return 0; return mul(fac[n], mul(invfac[n-k], invfac[k])); } void calcfac(int n, vector<int> &fac, vector<int> &invfac){ fac[0] = 1, invfac[0] = 1; for(int i = 1; i <= n; ++i) fac[i] = mul(fac[i-1], i); invfac[n] = inv(fac[n]); for(int i = n-1; i; --i) invfac[i] = mul(invfac[i+1], i+1); } void answer(){ int n; scanf("%d", &n); vv<int> cnt(n+1, 0); for(int i = 0, a; i < n; ++i) scanf("%d", &a), ++cnt[a]; vv<int> t; for(int i = 1; i <= n; ++i) if(cnt[i]) t.emplace_back(cnt[i]); sort(all(t)); int result = 0; for(int l = 0, r = ssize(t)-1; l <= r; --r){ if(l == r){ ++result; break; } int sum = 0; while(l < r && sum < t[r]-1){ if(t[r]-1 < sum+t[l]){ t[l] = sum+t[l]-(t[r]-1); break; } else sum += t[l], ++l; } //~ printf("%d %d\n", l, r); ++result; } printf("%d\n", result); } signed main(){ int T = 1; //~ scanf("%d", &T); //~ ios_base::sync_with_stdio(0); cin.tie(0); //cin >> T; for(++T; --T; ) answer(); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 | #pragma GCC optimize("O3") #include <bits/stdc++.h> #define fi first #define se second #define pn printf("\n") #define ssize(x) int(x.size()) #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() #define bitcount(x) __builtin_popcount(x) #define clz(x) __builtin_clz(x) #define ctz(x) __builtin_ctz(x) using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<int, ll> pil; typedef pair<ll, int> pli; typedef pair<ll, ll> pll; typedef double db; typedef long double ldb; #define vv vector /*void read(int &a){ char c = getchar_unlocked(); a = 0; while(c<'0' || '9'<c) c = getchar_unlocked(); while('0'<=c&&c<='9') a = (a<<3)+(a<<1)+c-'0', c = getchar_unlocked(); }*/ int inf = 2e09; ll infll = 2e18; int mod = (1<<23)*119+1; int add(int a, int b){return a+b >= mod ? a+b - mod : a+b;} int sub(int a, int b){return a-b < 0 ? a-b + mod : a-b;} int mul(int a, int b){return int(a * ll(b) % mod);} int fpow(int a, int b){ int ret = 1; while(b){ if(b & 1) ret = mul(ret, a); b >>= 1, a = mul(a, a); } return ret; } int inv(int a){ return fpow(a, mod-2); } int coeff(int n, int k, vector<int> &fac, vector<int> &invfac){ if(n < k) return 0; return mul(fac[n], mul(invfac[n-k], invfac[k])); } void calcfac(int n, vector<int> &fac, vector<int> &invfac){ fac[0] = 1, invfac[0] = 1; for(int i = 1; i <= n; ++i) fac[i] = mul(fac[i-1], i); invfac[n] = inv(fac[n]); for(int i = n-1; i; --i) invfac[i] = mul(invfac[i+1], i+1); } void answer(){ int n; scanf("%d", &n); vv<int> cnt(n+1, 0); for(int i = 0, a; i < n; ++i) scanf("%d", &a), ++cnt[a]; vv<int> t; for(int i = 1; i <= n; ++i) if(cnt[i]) t.emplace_back(cnt[i]); sort(all(t)); int result = 0; for(int l = 0, r = ssize(t)-1; l <= r; --r){ if(l == r){ ++result; break; } int sum = 0; while(l < r && sum < t[r]-1){ if(t[r]-1 < sum+t[l]){ t[l] = sum+t[l]-(t[r]-1); break; } else sum += t[l], ++l; } //~ printf("%d %d\n", l, r); ++result; } printf("%d\n", result); } signed main(){ int T = 1; //~ scanf("%d", &T); //~ ios_base::sync_with_stdio(0); cin.tie(0); //cin >> T; for(++T; --T; ) answer(); return 0; } |