/*
Things to notice:
1. do not calculate useless values
2. do not use similar names
 
Things to check:
1. submit the correct file
2. time (it is log^2 or log)
3. memory
4. prove your naive thoughts 
5. long long
6. corner case like n=0,1,inf or n=m
7. check if there is a mistake in the ds or other tools you use
8. fileio in some oi-contest
9. module on time 
10. the number of a same divisor in a math problem
11. multi-information and queries for dp and ds problems
*/
#include<bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define pii pair<int,int>
#define mp make_pair
#define pb push_back
const int mod=1e9+7;
const int inf=0x3f3f3f3f;
int n,K;
short perm[3005][3005];
int cnt0,cnt1,ans;
bool vis[3005][3005];
int fpow(int x,int b)
{
	if(x==0) return 0;
	if(b==0) return 1;
	int res=1;
	while(b>0)
	{
		if(b&1)	res=1LL*res*x%mod;
		x=1LL*x*x%mod;
		b>>=1;
	}
	return res;
}
void dfs0(short x,short y)
{
	if(x<y) cnt0++;
	else cnt1++;
	vis[x][y]=1;
	short *px=perm[x],*py=perm[y];
	for(short i=1;i<=K;i++) if(!vis[px[i]][py[i]]) dfs0(px[i],py[i]);
}
int a[3005];
mt19937 rnd(114514); 
void solve()
{
	cin>>n>>K;
	for(int i=1;i<=n;i++) a[i]=i;
	for(int i=1;i<=K;i++)
	{
//		for(int j=n;j>=1;j--) swap(a[j],a[rnd()%j+1]);
		for(int j=1;j<=n;j++) cin>>perm[j][i];
	}
	for(int i=1;i<=n;i++) for(int j=i+1;j<=n;j++) if(!vis[i][j])
	{
		cnt0=cnt1=0;
		dfs0(i,j);
//		cout<<i<<" "<<j<<" "<<cnt0<<" "<<cnt1<<"\n";
		ans=(ans+1LL*cnt0*cnt1%mod*fpow(cnt0+cnt1,mod-2)%mod)%mod;
	}
	cout<<ans<<"\n";
}
signed main()
{
//	freopen("input.txt","r",stdin);
	ios::sync_with_stdio(0);
	cin.tie(0);
	int _=1;
//	cin>>_;
	while(_--) solve();
	return 0;
}
        1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84  | /* Things to notice: 1. do not calculate useless values 2. do not use similar names Things to check: 1. submit the correct file 2. time (it is log^2 or log) 3. memory 4. prove your naive thoughts 5. long long 6. corner case like n=0,1,inf or n=m 7. check if there is a mistake in the ds or other tools you use 8. fileio in some oi-contest 9. module on time 10. the number of a same divisor in a math problem 11. multi-information and queries for dp and ds problems */ #include<bits/stdc++.h> using namespace std; #define fi first #define se second #define pii pair<int,int> #define mp make_pair #define pb push_back const int mod=1e9+7; const int inf=0x3f3f3f3f; int n,K; short perm[3005][3005]; int cnt0,cnt1,ans; bool vis[3005][3005]; int fpow(int x,int b) { if(x==0) return 0; if(b==0) return 1; int res=1; while(b>0) { if(b&1) res=1LL*res*x%mod; x=1LL*x*x%mod; b>>=1; } return res; } void dfs0(short x,short y) { if(x<y) cnt0++; else cnt1++; vis[x][y]=1; short *px=perm[x],*py=perm[y]; for(short i=1;i<=K;i++) if(!vis[px[i]][py[i]]) dfs0(px[i],py[i]); } int a[3005]; mt19937 rnd(114514); void solve() { cin>>n>>K; for(int i=1;i<=n;i++) a[i]=i; for(int i=1;i<=K;i++) { // for(int j=n;j>=1;j--) swap(a[j],a[rnd()%j+1]); for(int j=1;j<=n;j++) cin>>perm[j][i]; } for(int i=1;i<=n;i++) for(int j=i+1;j<=n;j++) if(!vis[i][j]) { cnt0=cnt1=0; dfs0(i,j); // cout<<i<<" "<<j<<" "<<cnt0<<" "<<cnt1<<"\n"; ans=(ans+1LL*cnt0*cnt1%mod*fpow(cnt0+cnt1,mod-2)%mod)%mod; } cout<<ans<<"\n"; } signed main() { // freopen("input.txt","r",stdin); ios::sync_with_stdio(0); cin.tie(0); int _=1; // cin>>_; while(_--) solve(); return 0; }  | 
            
        
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