// clang-format off #include<bits/stdc++.h> using namespace std; using LL=long long; #define FOR(i,l,r) for(auto i=(l);i<=(r);++i) #define REP(i,n) FOR(i,0,(n)-1) #define ssize(x) int(x.size()) template<class A,class B>auto&operator<<(ostream&o,pair<A,B>p){return o<<"("<<p.first<<", "<<p.second<<")";} template<class T>auto operator<<(ostream&o,T x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<(", ")+2*!i++<<e;return o<<"}";} #ifdef DEBUG #define debug(x...) cerr<<"["#x"]: ",[](auto...$){((cerr<<$<<"; "),...);}(x),cerr<<'\n' #else #define debug(...) {} #endif // clang-format on int main() { cin.tie(0)->sync_with_stdio(0); LL h, w, n, score = 0; cin >> h >> w >> n; vector<LL> seq(n); for (auto& x : seq) cin >> x; // Not possible LL hmod = h % seq.front(), wmod = w % seq.front(); if (hmod || wmod) { cout << "-1\n"; return 0; } REP (ptr, n - 1) { // Calculate the next hmod, wmod hmod = h % seq[ptr + 1], wmod = w % seq[ptr + 1]; // Make sure seq[ptr + 1] divides both w and h score += (hmod / seq[ptr]) * (w / seq[ptr]); h -= hmod; score += (wmod / seq[ptr]) * (h / seq[ptr]); w -= wmod; } score += (h / seq.back()) * (w / seq.back()); cout << score << "\n"; return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 | // clang-format off #include<bits/stdc++.h> using namespace std; using LL=long long; #define FOR(i,l,r) for(auto i=(l);i<=(r);++i) #define REP(i,n) FOR(i,0,(n)-1) #define ssize(x) int(x.size()) template<class A,class B>auto&operator<<(ostream&o,pair<A,B>p){return o<<"("<<p.first<<", "<<p.second<<")";} template<class T>auto operator<<(ostream&o,T x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<(", ")+2*!i++<<e;return o<<"}";} #ifdef DEBUG #define debug(x...) cerr<<"["#x"]: ",[](auto...$){((cerr<<$<<"; "),...);}(x),cerr<<'\n' #else #define debug(...) {} #endif // clang-format on int main() { cin.tie(0)->sync_with_stdio(0); LL h, w, n, score = 0; cin >> h >> w >> n; vector<LL> seq(n); for (auto& x : seq) cin >> x; // Not possible LL hmod = h % seq.front(), wmod = w % seq.front(); if (hmod || wmod) { cout << "-1\n"; return 0; } REP (ptr, n - 1) { // Calculate the next hmod, wmod hmod = h % seq[ptr + 1], wmod = w % seq[ptr + 1]; // Make sure seq[ptr + 1] divides both w and h score += (hmod / seq[ptr]) * (w / seq[ptr]); h -= hmod; score += (wmod / seq[ptr]) * (h / seq[ptr]); w -= wmod; } score += (h / seq.back()) * (w / seq.back()); cout << score << "\n"; return 0; } |