// Arti1990, II UWr #include <bits/stdc++.h> #define forr(i, n) for(int i=0; i<n; i++) #define FOREACH(iter, coll) for(auto iter = coll.begin(); iter != coll.end(); ++iter) #define FOREACHR(iter, coll) for(auto iter = coll.rbegin(); iter != coll.rend(); ++iter) #define lbound(P,K,FUN) ({auto SSS=P, PPP = P-1, KKK=(K)+1; while(PPP+1!=KKK) {SSS = (PPP+(KKK-PPP)/2); if(FUN(SSS)) KKK = SSS; else PPP = SSS;} PPP;}) #define testy() int _tests; cin>>_tests; FOR(_test, 1, _tests) #define CLEAR(tab) memset(tab, 0, sizeof(tab)) #define CONTAIN(el, coll) (coll.find(el) != coll.end()) #define FOR(i, a, b) for(int i=a; i<=b; i++) #define FORD(i, a, b) for(int i=a; i>=b; i--) #define MP make_pair #define PB push_back #define ff first #define ss second #define deb(X) X; #define SIZE(coll) ((int)coll.size()) #define M 1000000007 #define INF 1000000007LL using namespace std; int n, k, tab[3007][3007]; long long odwr[1000007]; map <int, vector<vector<int>>> mapa; pair <long long, long long> euklid(long long a, long long b) { if(b == 0) return make_pair(1, 0); pair <long long, long long> p = euklid(b, a%b); return make_pair(p.second, p.first - p.second * (a/b)); } long long odwrotnosc(long long a, long long mod) { long long e = euklid(a, mod).first; return (e < 0 ? mod-((-e) % mod) : (e % mod)); } void init() { FOR(i, 1, 3005) odwr[i] = odwrotnosc(i, M); } void solve1() { long long res = 0; FOR(i, 1, n) { int pos = i; vector <int> pozycje; do { pozycje.PB(pos); pos = tab[0][pos]; } while (pos != i); int dl = pozycje.size(); /*forr(i, pozycje.size()) { cout << dl << " " << i << " " << pozycje[i] << '\n'; }*/ forr(i, pozycje.size()) { for(auto &el : mapa) { int d = el.ff; int nwd = gcd(d, dl); for(int j = i%nwd; j < d; j += nwd) for(auto &x : el.ss[j]) if(x > pozycje[i]) { res = (res + odwr[d/nwd]*odwr[dl]) % M; } } } if(mapa.count(dl) == 0) mapa[dl] = vector<vector<int>>(dl); forr(i, pozycje.size()) mapa[dl][i].PB(pozycje[i]); } cout << res << '\n'; } int inwersje(vector <char> &v) { int ile = 0; forr(i, v.size()) forr(j, i) if(v[j] > v[i]) ile++; return ile; } vector <char> nakladaj(vector <char> &v, int nr) { vector <char> res(n, 0); forr(i, n) res[tab[nr][i+1]-1] = v[i]; return res; } void solvek() { set <vector<char>> byl; deque <vector<char>> todo; vector <char> v, v2; long long res = 0; FOR(i, 1, n) v.PB(i); byl.insert(v); todo.PB(v); while(!todo.empty()) { v = todo.front(); todo.pop_front(); res += inwersje(v); /* for(auto el : v) cerr << (int)el << " "; cerr << "-> inv: " << inwersje(v) << '\n'; */ forr(i, k) { v2 = nakladaj(v, i); if(byl.count(v2) == 0) { byl.insert(v2); todo.PB(v2); } } } //cout << res << '\n'; cout << res*odwrotnosc(byl.size(), M)%M << '\n'; } int solve() { cin >> n >> k; forr(j, k) FOR(i, 1, n) cin >> tab[j][i]; if(k == 1) solve1(); else solvek(); return 0; } int main() { std::ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); init(); solve(); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 | // Arti1990, II UWr #include <bits/stdc++.h> #define forr(i, n) for(int i=0; i<n; i++) #define FOREACH(iter, coll) for(auto iter = coll.begin(); iter != coll.end(); ++iter) #define FOREACHR(iter, coll) for(auto iter = coll.rbegin(); iter != coll.rend(); ++iter) #define lbound(P,K,FUN) ({auto SSS=P, PPP = P-1, KKK=(K)+1; while(PPP+1!=KKK) {SSS = (PPP+(KKK-PPP)/2); if(FUN(SSS)) KKK = SSS; else PPP = SSS;} PPP;}) #define testy() int _tests; cin>>_tests; FOR(_test, 1, _tests) #define CLEAR(tab) memset(tab, 0, sizeof(tab)) #define CONTAIN(el, coll) (coll.find(el) != coll.end()) #define FOR(i, a, b) for(int i=a; i<=b; i++) #define FORD(i, a, b) for(int i=a; i>=b; i--) #define MP make_pair #define PB push_back #define ff first #define ss second #define deb(X) X; #define SIZE(coll) ((int)coll.size()) #define M 1000000007 #define INF 1000000007LL using namespace std; int n, k, tab[3007][3007]; long long odwr[1000007]; map <int, vector<vector<int>>> mapa; pair <long long, long long> euklid(long long a, long long b) { if(b == 0) return make_pair(1, 0); pair <long long, long long> p = euklid(b, a%b); return make_pair(p.second, p.first - p.second * (a/b)); } long long odwrotnosc(long long a, long long mod) { long long e = euklid(a, mod).first; return (e < 0 ? mod-((-e) % mod) : (e % mod)); } void init() { FOR(i, 1, 3005) odwr[i] = odwrotnosc(i, M); } void solve1() { long long res = 0; FOR(i, 1, n) { int pos = i; vector <int> pozycje; do { pozycje.PB(pos); pos = tab[0][pos]; } while (pos != i); int dl = pozycje.size(); /*forr(i, pozycje.size()) { cout << dl << " " << i << " " << pozycje[i] << '\n'; }*/ forr(i, pozycje.size()) { for(auto &el : mapa) { int d = el.ff; int nwd = gcd(d, dl); for(int j = i%nwd; j < d; j += nwd) for(auto &x : el.ss[j]) if(x > pozycje[i]) { res = (res + odwr[d/nwd]*odwr[dl]) % M; } } } if(mapa.count(dl) == 0) mapa[dl] = vector<vector<int>>(dl); forr(i, pozycje.size()) mapa[dl][i].PB(pozycje[i]); } cout << res << '\n'; } int inwersje(vector <char> &v) { int ile = 0; forr(i, v.size()) forr(j, i) if(v[j] > v[i]) ile++; return ile; } vector <char> nakladaj(vector <char> &v, int nr) { vector <char> res(n, 0); forr(i, n) res[tab[nr][i+1]-1] = v[i]; return res; } void solvek() { set <vector<char>> byl; deque <vector<char>> todo; vector <char> v, v2; long long res = 0; FOR(i, 1, n) v.PB(i); byl.insert(v); todo.PB(v); while(!todo.empty()) { v = todo.front(); todo.pop_front(); res += inwersje(v); /* for(auto el : v) cerr << (int)el << " "; cerr << "-> inv: " << inwersje(v) << '\n'; */ forr(i, k) { v2 = nakladaj(v, i); if(byl.count(v2) == 0) { byl.insert(v2); todo.PB(v2); } } } //cout << res << '\n'; cout << res*odwrotnosc(byl.size(), M)%M << '\n'; } int solve() { cin >> n >> k; forr(j, k) FOR(i, 1, n) cin >> tab[j][i]; if(k == 1) solve1(); else solvek(); return 0; } int main() { std::ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); init(); solve(); return 0; } |