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#include<bits/stdc++.h>
using namespace std;
typedef long double ld;
typedef long long ll;
#define rep(a, b) for(ll a = 0; a < (b); ++a)
#define st first
#define nd second
#define pb push_back
#define all(a) a.begin(), a.end()
const ll MOD=1e9+7;
const int LIM=3e5+7;
struct item {
  ll sum=0, ile=0, dlu=0, suf=0;
};
vector<ll>poz;
ll A[LIM], B[LIM], T[LIM], wynik[2*LIM], n, m, X, N=1;
item tr[4*LIM];
vector<pair<ll,pair<ll,ll>>>P;
item lacz(item &a, item &b) {
  return {(a.sum+b.sum+(((b.ile*(m+1)-((b.ile*(b.ile-1)/2)%MOD)+MOD)*a.dlu)%MOD)-((a.suf*b.ile)%MOD)+MOD)%MOD,
    a.ile+b.ile, a.dlu+b.dlu, (a.suf+b.suf+a.dlu*b.ile)%MOD};
}
void upd(int v, ll x) {
  v+=N;
  tr[v].sum=((m+1)*(MOD+x-1)-((x*(x-1)/2)%MOD)+MOD)%MOD;
  tr[v].ile=tr[v].suf=x;
  v/=2;
  while(v>1) {
    tr[v]=lacz(tr[2*v], tr[2*v+1]);
    v/=2;
  }
}
void upd2(int v, ll x) {
  v+=N;
  tr[v].sum=((m+1)*(MOD+x-1)-((x*(x-1)/2)%MOD)+MOD)%MOD;
  tr[v].ile=tr[v].suf=x;
}
ll cnt(int l, int r) {
  if(l>r) return 0;
  l+=N; r+=N;
  item ansl=tr[l], ansr=tr[r];
  if(l==r) return ansl.sum;
  while(l/2!=r/2) {
    if(l%2==0) ansl=lacz(ansl, tr[l+1]);
    if(r%2==1) ansr=lacz(tr[r-1], ansr);
    l/=2; r/=2;
  }
  return lacz(ansl, ansr).sum;
}
ll pytaj(ll x) {
  ll a=0, b=-1;
  if(poz.size()) b=poz.back();
  if(poz.size()>m) a=poz[poz.size()-m-1]+1;
  ll ans=cnt(max(a, x), b);
  if(x<a) ans=(ans+(a-x)*X)%MOD;
  return ans;
}
void czysc(int v) {
  if(v>=N) {
    tr[v].ile=tr[v].suf=0;
    tr[v].sum=MOD-m-1;
    return;
  }
  if(tr[2*v].ile>0) czysc(2*v);
  if(tr[2*v+1].ile>0) czysc(2*v+1);
  tr[v].ile=tr[v].suf=0;
  tr[v].sum=(tr[2*v].sum+tr[2*v+1].sum)%MOD;
}
ll licz(ll k) {
  poz.clear();
  czysc(1);
  vector<pair<ll,ll>>S;
  rep(i, P.size()) {
    if(P[i].st>=k) S.pb(P[i].nd);
    else break;
  }
  sort(all(S));
  ll ans=(n*(n-1)/2)%MOD;
  ans=(ans*X)%MOD;
  if(!S.size()) return ans;
  rep(i, S.size()) {
    ll lst=S[i].st, aktile=0;
    for(ll j=S[i].st+k-1; j<=S[i].nd; j+=k-1) {
      ll p=pytaj(0);
      if(aktile) p=(p-tr[S[i].st+N].sum+MOD)%MOD;
      p=(p*(j-lst))%MOD;
      ans=(ans-p+MOD)%MOD;
      lst=j;
      ++aktile;
      if(aktile>m+1) break;
      upd2(S[i].st, aktile);
      poz.pb(S[i].st);
    }
    ll p=pytaj(0);
    if(aktile) p=(p-tr[S[i].st+N].sum+MOD)%MOD;
    p=(p*(S[i].nd-lst+1))%MOD;
    ans=(ans-p+MOD)%MOD;
    upd2(S[i].st, 0);
    while(poz.size() && poz.back()==S[i].st) poz.pop_back();
    ll xd=S[i].nd-k+1;
    while(xd-k+1>=S[i].st) xd-=k-1;
    for(ll j=xd; j<=S[i].nd-k+1; j+=k-1) {
      upd(j, 1);
      poz.pb(j);
    }
    p=pytaj(0);
    if(i+1==S.size()) p=(p*(n-2-S[i].nd))%MOD;
    else p=(p*(S[i+1].st-S[i].nd-1))%MOD;
    ans=(ans-p+MOD)%MOD;
  }
  rep(i, S.size()) {
    ll d=S[i].nd-S[i].st+1;
    for(ll x=1; x<=m; ++x) {
      ll q=(x+1)*(k-1);
      if(q>=d) break;
      ll p=d*(d+1)/2-q*d+q*(q-1)/2; 
      p%=MOD;
      p=(p*(m+1-x))%MOD;
      ans=(ans-p+MOD)%MOD;
    }
  }
  return ans;
}
void solve() {
  if(n==1) return;
  N=1;
  while(N<n) N*=2;
  rep(i, N) tr[N+i]={MOD-m-1, 0, 1};
  for(int i=N-1; i; --i) tr[i]=lacz(tr[2*i], tr[2*i+1]);
  X=(m*(m+1)/2)%MOD;
  rep(i, n-1) if(A[i]<A[i+1]) T[i]=1; else T[i]=0;
  P.clear();
  ll l=0;
  rep(i, n-2) if(T[i]!=T[i+1]) {
    P.pb({i-l+1, {l, i}});
    l=i+1;
  }
  P.pb({n-1-l, {l, n-2}});
  sort(all(P));
  reverse(all(P));
  vector<ll>ans(n+2);
  for(int k=n; k>=2; --k) {
    ans[k]=licz(k);
    if(k<n) ans[k+1]=(ans[k+1]-ans[k]+MOD)%MOD;
  }
  ll s=X;
  s=(s-m+MOD)%MOD;
  for(ll k=2; k<=n; ++k) {
    ll p=(s*(n+1-k))%MOD;
    ans[2]=(ans[2]-p+MOD)%MOD;
    if(k<=m) s=(s-(m+1-k)+MOD)%MOD;
  }
  for(ll k=2; k<=n; ++k) wynik[k]=(wynik[k]+ans[k])%MOD;
}
int main() {
  ios_base::sync_with_stdio(0); cin.tie(0);
  cin >> n >> m;
  rep(i, n) cin >> A[i];
  rep(i, m) cin >> B[i];
  rep(xd, 2) {
    solve();
    swap(n, m);
    rep(i, max(n, m)) swap(A[i], B[i]);
  }
  rep(i, min(n, m)) wynik[2]=(wynik[2]+(n-i)*(m-i))%MOD;
  rep(i, n+m) cout << wynik[i+1] << " ";
  cout << '\n';
}