#include <cstdio> #include <cmath> #include <iostream> #include <algorithm> #include <queue> #include <list> #include <vector> #include <map> #include <unordered_map> #include <unordered_set> #include <set> #include <bitset> #include <stack> #include <string> #include <cstring> #include <cassert> #include <limits.h> using namespace std; typedef unsigned long long LL; typedef long double LD; typedef vector<int> VI; #define REP(i,n) for(int i=0;i<(n);i++) #define FOR(i,a,b) for(VAR(i,a);i<=(b);++i) #define FORD(i,a,b) for(VAR(i,a);i>=(b);--i) #define FORE(a,b) for(VAR(a,(b).begin());a!=(b).end();++a) #define VAR(a,b) __typeof(b) a=(b) #define SIZE(a) ((int)((a).size())) #define ALL(x) (x).begin(),(x).end() #define CLR(x,a) memset(x,a,sizeof(x)) #define ZERO(x) memset(x,0,sizeof(x)) #define S(t,i) scanf("%" ## t, &i) #define SI(i) scanf("%d", &i) const int MAXN=1000+5; typedef unsigned long long BS; int n, m; LL r[MAXN][2]; BS rx[MAXN]; unordered_set<BS> s; // set<BS> s; LL p[] = {1ULL, 2ULL, 4ULL, 8ULL, 16ULL, 32ULL, 64ULL, 128ULL, 256ULL, 512ULL, 1024ULL, 2048ULL, 4096ULL, 8192ULL, 16384ULL, 32768ULL, 65536ULL, 131072ULL, 262144ULL, 524288ULL, 1048576ULL, 2097152ULL, 4194304ULL, 8388608ULL, 16777216ULL, 33554432ULL, 67108864ULL, 134217728ULL, 268435456ULL, 536870912ULL, 1073741824ULL, 2147483648ULL, 4294967296ULL, 8589934592ULL, 17179869184ULL, 34359738368ULL, 68719476736ULL}; inline void set_set(BS &s, int i) { s |= p[i]; } void print_BS(BS s) { FORD(i, 63, 0) { printf("%d", (s & (1ULL<<i)) == 0 ? 0 : 1); } printf("\n"); } // BS to_del[10000000]; // BS to_add[10000000]; // int tdi; // int tai; vector<BS> to_del; vector<BS> to_add; int solve(BS cs) { s.clear(); s.insert(cs); FORD(i, m-1, 0) { to_add.clear(); to_del.clear(); // tdi=0; // tai=0; FORE(si, s) { cs = *si; bool first = cs & r[i][0]; bool second = cs & r[i][1]; if (first == second) { to_add.push_back(cs); } else if (!first && second) { to_add.push_back(cs); to_add.push_back(cs ^ rx[i]); } else { to_del.push_back(cs); } // if (first == second) { // to_add[tai++] = cs; // } else if (!first && second) { // to_add[tai++] = cs; // to_add[tai++] = cs ^ rx[i]; // } else { // to_del[tdi++] = cs; // } } // REP(ti, tdi) { // s[s_curr].erase(to_del[ti]); // } // REP(ti, tai) { // s[s_curr].insert(to_add[ti]); // } FORE(m, to_del) { s.erase(*m); } FORE(m, to_add) { s.insert(*m); } } return s.size() & 1; } int main() { ios_base::sync_with_stdio(0); SI(n); SI(m); REP(i, m) { int r0, r1; SI(r0); SI(r1); r0--; r1--; r[i][0] = p[r0]; r[i][1] = p[r1]; rx[i] = r[i][0] | r[i][1]; } // BS tt=0; // set_set(tt, 0); // set_set(tt, 8); // simulate_ref(tt); // return 0; printf("%d ", n & 1); FOR(ik, 2, n-1) { int result = 0; BS cs = 0; REP(i, ik){ set_set(cs, i); } result += solve(cs); REP(i, n-ik) { cs <<= 1; result += solve(cs); } printf("%d ", result & 1); } printf("1"); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 | #include <cstdio> #include <cmath> #include <iostream> #include <algorithm> #include <queue> #include <list> #include <vector> #include <map> #include <unordered_map> #include <unordered_set> #include <set> #include <bitset> #include <stack> #include <string> #include <cstring> #include <cassert> #include <limits.h> using namespace std; typedef unsigned long long LL; typedef long double LD; typedef vector<int> VI; #define REP(i,n) for(int i=0;i<(n);i++) #define FOR(i,a,b) for(VAR(i,a);i<=(b);++i) #define FORD(i,a,b) for(VAR(i,a);i>=(b);--i) #define FORE(a,b) for(VAR(a,(b).begin());a!=(b).end();++a) #define VAR(a,b) __typeof(b) a=(b) #define SIZE(a) ((int)((a).size())) #define ALL(x) (x).begin(),(x).end() #define CLR(x,a) memset(x,a,sizeof(x)) #define ZERO(x) memset(x,0,sizeof(x)) #define S(t,i) scanf("%" ## t, &i) #define SI(i) scanf("%d", &i) const int MAXN=1000+5; typedef unsigned long long BS; int n, m; LL r[MAXN][2]; BS rx[MAXN]; unordered_set<BS> s; // set<BS> s; LL p[] = {1ULL, 2ULL, 4ULL, 8ULL, 16ULL, 32ULL, 64ULL, 128ULL, 256ULL, 512ULL, 1024ULL, 2048ULL, 4096ULL, 8192ULL, 16384ULL, 32768ULL, 65536ULL, 131072ULL, 262144ULL, 524288ULL, 1048576ULL, 2097152ULL, 4194304ULL, 8388608ULL, 16777216ULL, 33554432ULL, 67108864ULL, 134217728ULL, 268435456ULL, 536870912ULL, 1073741824ULL, 2147483648ULL, 4294967296ULL, 8589934592ULL, 17179869184ULL, 34359738368ULL, 68719476736ULL}; inline void set_set(BS &s, int i) { s |= p[i]; } void print_BS(BS s) { FORD(i, 63, 0) { printf("%d", (s & (1ULL<<i)) == 0 ? 0 : 1); } printf("\n"); } // BS to_del[10000000]; // BS to_add[10000000]; // int tdi; // int tai; vector<BS> to_del; vector<BS> to_add; int solve(BS cs) { s.clear(); s.insert(cs); FORD(i, m-1, 0) { to_add.clear(); to_del.clear(); // tdi=0; // tai=0; FORE(si, s) { cs = *si; bool first = cs & r[i][0]; bool second = cs & r[i][1]; if (first == second) { to_add.push_back(cs); } else if (!first && second) { to_add.push_back(cs); to_add.push_back(cs ^ rx[i]); } else { to_del.push_back(cs); } // if (first == second) { // to_add[tai++] = cs; // } else if (!first && second) { // to_add[tai++] = cs; // to_add[tai++] = cs ^ rx[i]; // } else { // to_del[tdi++] = cs; // } } // REP(ti, tdi) { // s[s_curr].erase(to_del[ti]); // } // REP(ti, tai) { // s[s_curr].insert(to_add[ti]); // } FORE(m, to_del) { s.erase(*m); } FORE(m, to_add) { s.insert(*m); } } return s.size() & 1; } int main() { ios_base::sync_with_stdio(0); SI(n); SI(m); REP(i, m) { int r0, r1; SI(r0); SI(r1); r0--; r1--; r[i][0] = p[r0]; r[i][1] = p[r1]; rx[i] = r[i][0] | r[i][1]; } // BS tt=0; // set_set(tt, 0); // set_set(tt, 8); // simulate_ref(tt); // return 0; printf("%d ", n & 1); FOR(ik, 2, n-1) { int result = 0; BS cs = 0; REP(i, ik){ set_set(cs, i); } result += solve(cs); REP(i, n-ik) { cs <<= 1; result += solve(cs); } printf("%d ", result & 1); } printf("1"); return 0; } |