#include <bits/stdc++.h> #define pb push_back using namespace std; typedef vector<int> vi; typedef pair<int, int> pii; const int mod = 1e9+7; long long odw(long long a) { long long w = mod-2; long long p = a; long long ans = 1; while(w) { if(w%2) ans = (ans*p) % mod; w /= 2; p = (p*p) % mod; } return ans; } vi L, R; vi nad; int main() { ios_base::sync_with_stdio(0); cin.tie(0); int n; cin >> n; L.pb(0); R.pb(0); nad.pb(0); for(int i = 1; i <= n; i++) { int li, ri; cin >> li >> ri; L.pb(li); R.pb(ri); } for(int i = 1; i <= n; i++) { int count = 1; int left = L[i], right = R[i]; for(int j = i+1; j <= n; j++) { if(R[j] < left || right < L[j]) continue; else if(left < L[j] && L[j] < right) { count++; right = max(right, R[j]); } else if(left < R[j] && R[j] < right) { count++; left = min(left, L[j]); } else break; } nad.pb(count); } long long ans = 0; for(int i = 1; i <= n; i++) ans = (ans + odw(nad[i])) % mod; cout << ans << "\n"; return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 | #include <bits/stdc++.h> #define pb push_back using namespace std; typedef vector<int> vi; typedef pair<int, int> pii; const int mod = 1e9+7; long long odw(long long a) { long long w = mod-2; long long p = a; long long ans = 1; while(w) { if(w%2) ans = (ans*p) % mod; w /= 2; p = (p*p) % mod; } return ans; } vi L, R; vi nad; int main() { ios_base::sync_with_stdio(0); cin.tie(0); int n; cin >> n; L.pb(0); R.pb(0); nad.pb(0); for(int i = 1; i <= n; i++) { int li, ri; cin >> li >> ri; L.pb(li); R.pb(ri); } for(int i = 1; i <= n; i++) { int count = 1; int left = L[i], right = R[i]; for(int j = i+1; j <= n; j++) { if(R[j] < left || right < L[j]) continue; else if(left < L[j] && L[j] < right) { count++; right = max(right, R[j]); } else if(left < R[j] && R[j] < right) { count++; left = min(left, L[j]); } else break; } nad.pb(count); } long long ans = 0; for(int i = 1; i <= n; i++) ans = (ans + odw(nad[i])) % mod; cout << ans << "\n"; return 0; } |