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#include <vector>
#include <cstdio>
#include <stack>
#include <algorithm>
#include <queue>
#include <map>
#include <cmath>
#include <unordered_set>
#include <unordered_map>
#include <set>
#include <cstring>
#include <bitset>
#include <iostream>
#include <queue>
#include <iomanip>
#include <complex>

using namespace std;

#define ALL(x) x.begin(), x.end()
#define UNIQUE(c) (c).resize(unique(ALL(c)) - (c).begin())
#define FOR(i, a, b) for(int i =(a); i <=(b); ++i)
#define RE(i, n) FOR(i, 1, n)
#define RED(i, n) FORD(i, n, 1)
#define FORD(i, a, b) for(int i = (a); i >= (b); --i)
#define REP(i, n) for(int i = 0;i <(n); ++i)
#define REPD(i, n) FORD(i, n-1,0)

#define printA(a, L, R) FOR(i,L,R) cout << a[i] << (i==R?'\n':' ')
#define printV(a) printA(a,0,a.size()-1)
#define PRESENT(c, x) ((c).find(x) != (c).end())
#define CPRESENT(c, x) (find(ALL(c),x) != (c).end())
#define bit(x, i) (x&(1<<i))
#define lowbit(x) ((x)&((x)^((x)-1)))

const int fx[4][2] = {{0,  1},
                      {0,  -1},
                      {1,  0},
                      {-1, 0}};
const int fxx[8][2] = {{0,  1},
                       {0,  -1},
                       {1,  0},
                       {-1, 0},
                       {1,  1},
                       {1,  -1},
                       {-1, 1},
                       {-1, -1}};
const int sk[8][2] = {{2,  1},
                      {2,  -1},
                      {-2, -1},
                      {-2, 1},
                      {1,  2},
                      {-1, 2},
                      {1,  -2},
                      {-1, -2}};

const int maxn = 8012;
long long mod = 998244353ll;
const long long inf = 10000000000012ll;

int n,k,t, pre1[maxn], pre2[maxn], res = - 1, nk, zos;
string s;
void solve() {
  cin>>n>>k>>t>>s;
    RE(i, n) {
        pre1[i] = pre1[i - 1] + (s[i - 1] == '1');
        pre2[i] = pre2[i - 1] + (s[i - 1] == '2');
    }
    if (k >= pre1[n]) {
        res = n + min(0, k - pre1[n] - pre2[n]);
    }
    RE(i, n) {
        FOR(j, i + 2 * t, n) {
            nk = k - pre1[i + t - 1] - (pre1[n] - pre1[j - t]) - (pre2[i + t - 1] - pre2[i - 1]) - (pre2[j] - pre2[j - t]);
            if (nk >= 0) {
                zos = pre2[n] - (pre2[j] - pre2[i - 1]);
                res = max(res, n - (j - i + 1) - max(0, (zos - nk)));
            }
        }
    }
    cout<<res<<"\n";
}

int main() {
    ios_base::sync_with_stdio(false), cin.tie(nullptr);

    int tt = 1;
//    cin >> tt;`
    while (tt--) {
        solve();
    }
    return 0;
}