#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define st first
#define nd second
typedef long long ll;
typedef long double ld;
const ll I = 1000'000'000'000'000'000LL;
const int II = 2'000'000'000;
const ll M = 1000'000'007LL;
const ld E = 0.00001;
const int N = 50'007;
const int K = 1'500;
ld tab[N];
vector<ld> ws[N];
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef complex<double> C;
typedef vector<long double> vd;
void fft(vector<C>& a) {
int n = sz(a), L = 31 - __builtin_clz(n);
static vector<complex<long double>> R(2, 1);
static vector<C> rt(2, 1); // (^ 10% faster if double)
for (static int k = 2; k < n; k *= 2) {
R.resize(n); rt.resize(n);
auto x = polar(1.0L, acos(-1.0L) / k);
rep(i,k,2*k) rt[i] = R[i] = i&1 ? R[i/2] * x : R[i/2];
}
vi rev(n);
rep(i,0,n) rev[i] = (rev[i / 2] | (i & 1) << L) / 2;
rep(i,0,n) if (i < rev[i]) swap(a[i], a[rev[i]]);
for (int k = 1; k < n; k *= 2)
for (int i = 0; i < n; i += 2 * k) rep(j,0,k) {
// C z = rt[j+k] * a[i+j+k]; // (25% faster if hand-rolled) /// include-line
auto x = (double *)&rt[j+k], y = (double *)&a[i+j+k]; /// exclude-line
C z(x[0]*y[0] - x[1]*y[1], x[0]*y[1] + x[1]*y[0]); /// exclude-line
a[i + j + k] = a[i + j] - z;
a[i + j] += z;
}
}
vd conv(const vd& a, const vd& b) {
if (a.empty() || b.empty()) return {};
vd res(sz(a) + sz(b) - 1);
int L = 32 - __builtin_clz(sz(res)), n = 1 << L;
vector<C> in(n), out(n);
copy(all(a), begin(in));
rep(i,0,sz(b)) in[i].imag(b[i]);
fft(in);
for (C& x : in) x *= x;
rep(i,0,n) out[i] = in[-i & (n - 1)] - conj(in[i]);
fft(out);
rep(i,0,sz(res)) res[i] = imag(out[i]) / (4 * n);
return res;
}
void Solve()
{
int n, k;
double a;
cin >> n >> k;
for(int i = 1; i <= n; ++i)
{
cin >> a; tab[i] = a;
}
ld answer = 0;
sort(tab + 1, tab + 1 + n);
reverse(tab + 1, tab + 1 + n);
vector<ld> cur = {1}; int d = 0;
cout << fixed << setprecision(3);
for(int i = 1; i <= n; i += K)
{
/*cout << "S: " << i << "\n";
for(int i = 0; i < (int)cur.size(); ++i)
cout << cur[i] << " ";
cout << "\n";*/
vector<ld> akt((2 * K + 1), 0);
int da = K;
vector<ld> nw((2 * K + 1), 0);
akt[da] = (ld)1;
ld cans = 0;
for(int j = k + K; j < i && j + d < (int)cur.size(); ++j)
cans += cur[j + d];
vector<ld> ca; int dd = -(k - K);
for(int j = k - K; j <= k + K - 1; ++j)
if(j + d < 0 || j + d >= (int)cur.size())
ca.pb((ld)0);
else
ca.pb(cur[j + d]);
vector<ld> hl((int)ca.size(), 0);
ca.pb(0);
for(int r = 1; r <= min(K, n - i + 1); ++r)
{
int j = i + r - 1;
ld dod = ca[k + K - 1 + dd] * tab[j];
for(int l = k - K + 1; l <= k + K - 1; ++l)
{
int a = l + dd;
hl[a] = ca[a - 1] * tab[j] + ca[a + 1] * ((ld)1 - tab[j]);
if(l >= k) dod += hl[a];
}
answer = max(answer, cans + dod);
for(int l = k - K; l <= k + K - 1; ++l)
ca[l + dd] = hl[l + dd];
}
for(int r = 1; r <= min(K, n - i + 1); ++r)
{
int j = i + r - 1;
for(int l = -r; l <= r; l += 2)
{
int a = l + da;
if(a > 0)
nw[a] += akt[a - 1] * tab[j];
if(a < 2 * K)
nw[a] += akt[a + 1] * ((ld)1 - tab[j]);
}
for(int l = -r; l <= r; ++l)
{akt[l + da] = nw[l + da]; nw[l + da] = 0;}
}
/*cout << "E: \n";
for(int i = 0; i < (int)akt.size(); ++i)
cout << akt[i] << " ";
cout << "\n\n";*/
if(i + K <= n)
{
//int siz = (int)akt.size() - 1 + (int)cur.size();
d += da;
nw = conv(cur, akt);
cur = nw;
}
}
cout << fixed << setprecision(9) << answer << "\n";
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
//int t; cin >> t;
//while(t--)
Solve();
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 | #include <bits/stdc++.h> using namespace std; #define pb push_back #define st first #define nd second typedef long long ll; typedef long double ld; const ll I = 1000'000'000'000'000'000LL; const int II = 2'000'000'000; const ll M = 1000'000'007LL; const ld E = 0.00001; const int N = 50'007; const int K = 1'500; ld tab[N]; vector<ld> ws[N]; #define rep(i, a, b) for(int i = a; i < (b); ++i) #define all(x) begin(x), end(x) #define sz(x) (int)(x).size() typedef long long ll; typedef pair<int, int> pii; typedef vector<int> vi; typedef complex<double> C; typedef vector<long double> vd; void fft(vector<C>& a) { int n = sz(a), L = 31 - __builtin_clz(n); static vector<complex<long double>> R(2, 1); static vector<C> rt(2, 1); // (^ 10% faster if double) for (static int k = 2; k < n; k *= 2) { R.resize(n); rt.resize(n); auto x = polar(1.0L, acos(-1.0L) / k); rep(i,k,2*k) rt[i] = R[i] = i&1 ? R[i/2] * x : R[i/2]; } vi rev(n); rep(i,0,n) rev[i] = (rev[i / 2] | (i & 1) << L) / 2; rep(i,0,n) if (i < rev[i]) swap(a[i], a[rev[i]]); for (int k = 1; k < n; k *= 2) for (int i = 0; i < n; i += 2 * k) rep(j,0,k) { // C z = rt[j+k] * a[i+j+k]; // (25% faster if hand-rolled) /// include-line auto x = (double *)&rt[j+k], y = (double *)&a[i+j+k]; /// exclude-line C z(x[0]*y[0] - x[1]*y[1], x[0]*y[1] + x[1]*y[0]); /// exclude-line a[i + j + k] = a[i + j] - z; a[i + j] += z; } } vd conv(const vd& a, const vd& b) { if (a.empty() || b.empty()) return {}; vd res(sz(a) + sz(b) - 1); int L = 32 - __builtin_clz(sz(res)), n = 1 << L; vector<C> in(n), out(n); copy(all(a), begin(in)); rep(i,0,sz(b)) in[i].imag(b[i]); fft(in); for (C& x : in) x *= x; rep(i,0,n) out[i] = in[-i & (n - 1)] - conj(in[i]); fft(out); rep(i,0,sz(res)) res[i] = imag(out[i]) / (4 * n); return res; } void Solve() { int n, k; double a; cin >> n >> k; for(int i = 1; i <= n; ++i) { cin >> a; tab[i] = a; } ld answer = 0; sort(tab + 1, tab + 1 + n); reverse(tab + 1, tab + 1 + n); vector<ld> cur = {1}; int d = 0; cout << fixed << setprecision(3); for(int i = 1; i <= n; i += K) { /*cout << "S: " << i << "\n"; for(int i = 0; i < (int)cur.size(); ++i) cout << cur[i] << " "; cout << "\n";*/ vector<ld> akt((2 * K + 1), 0); int da = K; vector<ld> nw((2 * K + 1), 0); akt[da] = (ld)1; ld cans = 0; for(int j = k + K; j < i && j + d < (int)cur.size(); ++j) cans += cur[j + d]; vector<ld> ca; int dd = -(k - K); for(int j = k - K; j <= k + K - 1; ++j) if(j + d < 0 || j + d >= (int)cur.size()) ca.pb((ld)0); else ca.pb(cur[j + d]); vector<ld> hl((int)ca.size(), 0); ca.pb(0); for(int r = 1; r <= min(K, n - i + 1); ++r) { int j = i + r - 1; ld dod = ca[k + K - 1 + dd] * tab[j]; for(int l = k - K + 1; l <= k + K - 1; ++l) { int a = l + dd; hl[a] = ca[a - 1] * tab[j] + ca[a + 1] * ((ld)1 - tab[j]); if(l >= k) dod += hl[a]; } answer = max(answer, cans + dod); for(int l = k - K; l <= k + K - 1; ++l) ca[l + dd] = hl[l + dd]; } for(int r = 1; r <= min(K, n - i + 1); ++r) { int j = i + r - 1; for(int l = -r; l <= r; l += 2) { int a = l + da; if(a > 0) nw[a] += akt[a - 1] * tab[j]; if(a < 2 * K) nw[a] += akt[a + 1] * ((ld)1 - tab[j]); } for(int l = -r; l <= r; ++l) {akt[l + da] = nw[l + da]; nw[l + da] = 0;} } /*cout << "E: \n"; for(int i = 0; i < (int)akt.size(); ++i) cout << akt[i] << " "; cout << "\n\n";*/ if(i + K <= n) { //int siz = (int)akt.size() - 1 + (int)cur.size(); d += da; nw = conv(cur, akt); cur = nw; } } cout << fixed << setprecision(9) << answer << "\n"; } int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); //int t; cin >> t; //while(t--) Solve(); return 0; } |
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