#include <vector> #include <cstdio> #include <stack> #include <algorithm> #include <queue> #include <map> #include <cmath> #include <unordered_set> #include <unordered_map> #include <set> #include <cstring> #include <bitset> #include <iostream> #include <queue> #include <iomanip> #include <complex> using namespace std; #define ALL(x) x.begin(), x.end() #define UNIQUE(c) (c).resize(unique(ALL(c)) - (c).begin()) #define FOR(i, a, b) for(int i =(a); i <=(b); ++i) #define RE(i, n) FOR(i, 1, n) #define RED(i, n) FORD(i, n, 1) #define FORD(i, a, b) for(int i = (a); i >= (b); --i) #define REP(i, n) for(int i = 0;i <(n); ++i) #define REPD(i, n) FORD(i, n-1,0) #define printA(a, L, R) FOR(i,L,R) cout << a[i] << (i==R?'\n':' ') #define printV(a) printA(a,0,a.size()-1) #define PRESENT(c, x) ((c).find(x) != (c).end()) #define CPRESENT(c, x) (find(ALL(c),x) != (c).end()) #define bit(x, i) (x&(1<<i)) #define lowbit(x) ((x)&((x)^((x)-1))) const int fx[4][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}}; const int fxx[8][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}, {1, 1}, {1, -1}, {-1, 1}, {-1, -1}}; const int sk[8][2] = {{2, 1}, {2, -1}, {-2, -1}, {-2, 1}, {1, 2}, {-1, 2}, {1, -2}, {-1, -2}}; const int maxn = 50012; long long mod = 998244353ll; const long long inf = 10000000000012ll; int n, t, mi, ma, po; double p[maxn],res,b[2][maxn * 2], je = 1, eps = 0.000001; bool akt; void solve() { cin>>n>>t; REP(i, n) cin>>p[i]; sort(p, p + n, [](auto a, auto b) { return a > b; }); if (t%2 == 1) { po = 1; b[akt][n + 1] = p[0]; b[akt][n - 1] = 1 - p[0]; mi = n - 1; ma = n + 1; if (t == 1)res = p[0]; } else { b[akt][n] = 1; mi = n; ma = n; } for (int i = po; i < n; i += 2) { FOR(j, mi, ma) { b[!akt][j - 2] += b[akt][j] * (je - p[i]) * (je - p[i + 1]); b[!akt][j] += b[akt][j] * ((je - p[i]) * p[i + 1] + (je - p[i + 1]) * p[i]); b[!akt][j + 2] = b[akt][j] * p[i] * p[i + 1]; } double wyn = 0; mi-=2; ma+=2; FOR(j, n + t, ma) { wyn += b[!akt][j]; } res = max(res, wyn); if (wyn > eps && res - wyn > eps)break; akt = !akt; } cout << fixed << setprecision(20) <<res<<"\n"; } int main() { ios_base::sync_with_stdio(false), cin.tie(nullptr); int tt = 1; // cin >> tt;` while (tt--) { solve(); } return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 | #include <vector> #include <cstdio> #include <stack> #include <algorithm> #include <queue> #include <map> #include <cmath> #include <unordered_set> #include <unordered_map> #include <set> #include <cstring> #include <bitset> #include <iostream> #include <queue> #include <iomanip> #include <complex> using namespace std; #define ALL(x) x.begin(), x.end() #define UNIQUE(c) (c).resize(unique(ALL(c)) - (c).begin()) #define FOR(i, a, b) for(int i =(a); i <=(b); ++i) #define RE(i, n) FOR(i, 1, n) #define RED(i, n) FORD(i, n, 1) #define FORD(i, a, b) for(int i = (a); i >= (b); --i) #define REP(i, n) for(int i = 0;i <(n); ++i) #define REPD(i, n) FORD(i, n-1,0) #define printA(a, L, R) FOR(i,L,R) cout << a[i] << (i==R?'\n':' ') #define printV(a) printA(a,0,a.size()-1) #define PRESENT(c, x) ((c).find(x) != (c).end()) #define CPRESENT(c, x) (find(ALL(c),x) != (c).end()) #define bit(x, i) (x&(1<<i)) #define lowbit(x) ((x)&((x)^((x)-1))) const int fx[4][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}}; const int fxx[8][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}, {1, 1}, {1, -1}, {-1, 1}, {-1, -1}}; const int sk[8][2] = {{2, 1}, {2, -1}, {-2, -1}, {-2, 1}, {1, 2}, {-1, 2}, {1, -2}, {-1, -2}}; const int maxn = 50012; long long mod = 998244353ll; const long long inf = 10000000000012ll; int n, t, mi, ma, po; double p[maxn],res,b[2][maxn * 2], je = 1, eps = 0.000001; bool akt; void solve() { cin>>n>>t; REP(i, n) cin>>p[i]; sort(p, p + n, [](auto a, auto b) { return a > b; }); if (t%2 == 1) { po = 1; b[akt][n + 1] = p[0]; b[akt][n - 1] = 1 - p[0]; mi = n - 1; ma = n + 1; if (t == 1)res = p[0]; } else { b[akt][n] = 1; mi = n; ma = n; } for (int i = po; i < n; i += 2) { FOR(j, mi, ma) { b[!akt][j - 2] += b[akt][j] * (je - p[i]) * (je - p[i + 1]); b[!akt][j] += b[akt][j] * ((je - p[i]) * p[i + 1] + (je - p[i + 1]) * p[i]); b[!akt][j + 2] = b[akt][j] * p[i] * p[i + 1]; } double wyn = 0; mi-=2; ma+=2; FOR(j, n + t, ma) { wyn += b[!akt][j]; } res = max(res, wyn); if (wyn > eps && res - wyn > eps)break; akt = !akt; } cout << fixed << setprecision(20) <<res<<"\n"; } int main() { ios_base::sync_with_stdio(false), cin.tie(nullptr); int tt = 1; // cin >> tt;` while (tt--) { solve(); } return 0; } |