/* * Opis: Główny nagłówek */ #include<bits/stdc++.h> using namespace std; using LL=long long; #define FOR(i,l,r)for(int i=(l);i<=(r);++i) #define REP(i,n)FOR(i,0,(n)-1) #define ssize(x)int(x.size()) #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif constexpr int W = 1e6 + 5; constexpr int inf = 1e9; constexpr int R = 2005; int all_triples(int a) { return (int) min((LL)inf, LL(a) * (a - 1) * (a - 2) / 6); } int all_doubles(int a) { return (int) min((LL)inf, LL(a) * (a - 1) / 2); } void solve() { int n; cin >> n; vector<int> arr; REP(i, n) { int a; cin >> a; if (a != 0) { arr.push_back(a); } } n = ssize(arr); vector<int> initial(n); REP(i, n) { initial[i] = (int) min(LL(W), i * LL(n-i-1)); } debug(initial); vector<int> at_most(n); REP(i, n) { while (all_triples(at_most[i] + 1) + initial[i] < arr[i]) { at_most[i]++; } } debug(at_most); vector<int> dp, temp; // for each sum count smalles requirement dp.push_back(0); REP(i, n) { if (initial[i] >= arr[i]) { continue; } temp.resize(ssize(dp) + at_most[i], inf); if (ssize(temp) > R) { temp.resize(R); } vector<int> interesting; // int start = 0; REP(j, ssize(dp)) { if (dp[j] + j > R) { continue; } if (j > 0 && dp[j] == dp[j-1]) { continue; } interesting.push_back(j); } if (i % 10 == 0) { debug(i, ssize(interesting)); } // while (dp[start] > 2 * R) { // start++; // } REP(j, at_most[i] + 1) { int base = initial[i] + all_triples(j + 1); base = min(base, inf); // FOR(k, start, ssize(dp)-1) { for (int k : interesting) { if (k + j >= R) { continue; } int prv = k + i; int req = dp[k]; LL tmp = base + (LL) all_doubles(j + 1) * prv; int curr = (int) min((LL) inf, (LL) tmp); int rest = max(0, arr[i] - curr); // debug("HEJO", i, j, k); // debug(prv, req, curr, rest); tmp = all_doubles(j + 1) + (LL) (j + 1) * prv; rest += (int) min((LL)inf, LL(i) * (n-i-1)); int slope = (int) min((LL) inf, tmp); int on_right = inf; if (slope != 0) { on_right = (rest + slope - 1) / slope; } on_right = max(0, on_right - (n-i-1)); int new_req = max(on_right, req - j); // if (new_req < temp[k + j]) { // debug("I DID IT!!!", new_req, k + j); // } temp[k + j] = min(temp[k + j], new_req); } } while (ssize(temp) > 1 && temp[ssize(temp)-2] == 0) { temp.pop_back(); } swap(dp, temp); temp.clear(); // debug("FINISHING", i); // debug(dp); } int res = inf; REP(i, ssize(dp)) { if (dp[i] == 0) { res = i; break; } } cout << res + n << "\n"; } int main() { cin.tie(0)->sync_with_stdio(0); int t; cin >> t; while (t--) { solve(); } }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 | /* * Opis: Główny nagłówek */ #include<bits/stdc++.h> using namespace std; using LL=long long; #define FOR(i,l,r)for(int i=(l);i<=(r);++i) #define REP(i,n)FOR(i,0,(n)-1) #define ssize(x)int(x.size()) #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif constexpr int W = 1e6 + 5; constexpr int inf = 1e9; constexpr int R = 2005; int all_triples(int a) { return (int) min((LL)inf, LL(a) * (a - 1) * (a - 2) / 6); } int all_doubles(int a) { return (int) min((LL)inf, LL(a) * (a - 1) / 2); } void solve() { int n; cin >> n; vector<int> arr; REP(i, n) { int a; cin >> a; if (a != 0) { arr.push_back(a); } } n = ssize(arr); vector<int> initial(n); REP(i, n) { initial[i] = (int) min(LL(W), i * LL(n-i-1)); } debug(initial); vector<int> at_most(n); REP(i, n) { while (all_triples(at_most[i] + 1) + initial[i] < arr[i]) { at_most[i]++; } } debug(at_most); vector<int> dp, temp; // for each sum count smalles requirement dp.push_back(0); REP(i, n) { if (initial[i] >= arr[i]) { continue; } temp.resize(ssize(dp) + at_most[i], inf); if (ssize(temp) > R) { temp.resize(R); } vector<int> interesting; // int start = 0; REP(j, ssize(dp)) { if (dp[j] + j > R) { continue; } if (j > 0 && dp[j] == dp[j-1]) { continue; } interesting.push_back(j); } if (i % 10 == 0) { debug(i, ssize(interesting)); } // while (dp[start] > 2 * R) { // start++; // } REP(j, at_most[i] + 1) { int base = initial[i] + all_triples(j + 1); base = min(base, inf); // FOR(k, start, ssize(dp)-1) { for (int k : interesting) { if (k + j >= R) { continue; } int prv = k + i; int req = dp[k]; LL tmp = base + (LL) all_doubles(j + 1) * prv; int curr = (int) min((LL) inf, (LL) tmp); int rest = max(0, arr[i] - curr); // debug("HEJO", i, j, k); // debug(prv, req, curr, rest); tmp = all_doubles(j + 1) + (LL) (j + 1) * prv; rest += (int) min((LL)inf, LL(i) * (n-i-1)); int slope = (int) min((LL) inf, tmp); int on_right = inf; if (slope != 0) { on_right = (rest + slope - 1) / slope; } on_right = max(0, on_right - (n-i-1)); int new_req = max(on_right, req - j); // if (new_req < temp[k + j]) { // debug("I DID IT!!!", new_req, k + j); // } temp[k + j] = min(temp[k + j], new_req); } } while (ssize(temp) > 1 && temp[ssize(temp)-2] == 0) { temp.pop_back(); } swap(dp, temp); temp.clear(); // debug("FINISHING", i); // debug(dp); } int res = inf; REP(i, ssize(dp)) { if (dp[i] == 0) { res = i; break; } } cout << res + n << "\n"; } int main() { cin.tie(0)->sync_with_stdio(0); int t; cin >> t; while (t--) { solve(); } } |