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#include <bits/stdc++.h>
using namespace std;
#define fwd(i, a, n) for (int i = (a); i < (n); i++)
#define rep(i, n) fwd(i, 0, n)
#define all(X) X.begin(), X.end()
#define sz(X) int(size(X))
#define pb push_back
#define eb emplace_back
#define st first
#define nd second
using pii = pair<int, int>; using vi = vector<int>;
using ll = long long; using ld = long double;
#ifdef LOC
auto SS = signal(6, [](int) { *(int *)0 = 0; });
#define DTP(x, y) auto operator<<(auto &o, auto a) -> decltype(y, o) { o << "("; x; return o << ")"; }
auto operator<<(auto &o, auto a) -> decltype(all(a), o);
DTP(o << a.st << ", " << a.nd, a.nd);
DTP(for (auto i : a) o << i << ", ", all(a));
#define deb(x...) cerr << setw(4) << __LINE__ << ":[" #x "]: ", [](auto... arg_) { (( cerr << arg_ << ", " ), ...) << '\n'; }(x)
#else
#define deb(...) 0
#endif

int P, phiP;
struct mint {
    int x = 0;
    mint operator+(mint o) const {return {x + o.x >= P ? x + o.x - P : x + o.x}; }
    mint operator-(mint o) const {return {x < o.x ? x - o.x + P : x - o.x}; }
    mint operator+() const {return *this; }
    mint operator-() const {return {x ? P - x : 0}; }
    mint operator*(mint o) const {return {int(ll(x) * o.x % P)}; }
    mint operator/(mint o) const {return *this * o.inv(); }
    mint & operator+=(mint o) {return *this = *this + o; }
    mint & operator-=(mint o) {return *this = *this - o; }
    mint & operator*=(mint o) {return *this = *this * o; }
    mint & operator/=(mint o) {return *this = *this / o; }
    mint pow(ll e) const {
        mint ret{1}, b(*this);
        for (; e; e >>= 1) {
            if (e & 1)
                ret *= b;
            b *= b;
        }
        return ret;
    }
    mint inv() const {return pow(phiP - 1); }
};

array<mint, int(1e6) + 6> fact, ifact, invs, sfact;

void initmint() {
    fact[0] = ifact[0] = sfact[0] = mint{1};
    fact[1] = ifact[1] = sfact[1] = invs[1] = mint{1};
    fwd(i, 2, sz(fact)) {
        invs[i] = -mint{P / i} * invs[P % i];
        fact[i] = fact[i-1] * mint{i};
        ifact[i] = ifact[i-1] * invs[i];
        sfact[i] = sfact[i-1] * fact[i];
    }
};

auto &operator<<(auto &os, mint m) {
    return os << m.x - (2 * m.x >= P && &os == &cerr ? P : 0);
}

mint evalCatConvFast(int n, int x, int skip) {
    mint r{1};

    fwd(i, 1, n) {
        int donate = max((skip+1-i)/2, 0);

        int tu = n-i - donate;
        assert(tu >= 0);

        // deb(i, n, skip, donate, tu);

        r *= mint(x+i).pow(tu);
        r *= mint(x+1-i).pow(donate);
    }

    return r;
}
mint evalOtherCatConv(int n, int x, int skip) {
    mint r{1};

    fwd(i, 1, n) {
        r *= mint{x+i}.pow(max(0, n-i-skip));
    }

    vi zera;
    rep(idskip, skip) {
        for (int &i : zera) i -= 2;

        rep(xx, n-1-idskip)
            zera.pb(-idskip-1+xx*2);
    }

    for (int i : zera)
        r *= mint{2*x + i};

    return r;
}

mint evalValue(int a, int b, int skip) {
    mint p1 = evalCatConvFast(a, b, skip);
    mint p2 = evalOtherCatConv(a, b, skip);

    vi values(a, b);
    rep(i, skip)
        values[i] -= skip - i;

    mint ret = fact[accumulate(all(values), 0)];
    for (int i : values)
        ret *= ifact[i];
    ret *= ret;

    ret *= p1.inv();
    ret *= p2.inv();

    return ret;
}
const int MAXA = 21;
array<array<mint, MAXA + 1>, MAXA + 1> multipliers;
mint evalValueWithMultiplier(int a, int b, int skip) {
    mint el = evalValue(a, b, skip);
    mint mu = multipliers[a][skip];
    return el * mu;
}

void initmuls() {
    fwd(a, 1, MAXA + 1) {
        multipliers[a][0] = sfact[a-1].pow(2);
        multipliers[a][a-1] = multipliers[a][0] * mint{2}.pow(a * (a-1) / 2);

        fwd(skip, 1, a - 1) {
            mint shouldBe = evalValueWithMultiplier(skip + 1, a, skip);
            mint our = evalValue(a, skip + 1, skip);
            multipliers[a][skip] = shouldBe * our.inv();
        }
    }
}

void solve() {
    int a, b, c;
    cin >> a >> b >> c >> P;

    phiP = P - 1;
    initmint();
    initmuls();

    c = a + b - 1 - c;

    mint ans = evalValueWithMultiplier(a, b, c);
    int n = a * b - c * (c + 1) / 2;

    cout << n << ' ' << ans.x << '\n';
    // cout << (ans + mint{n}).x << '\n';
}

int32_t main() {
    cin.tie(0)->sync_with_stdio(0);
    cout << fixed << setprecision(10);

    int z = 1;
    // cin >> z;
    rep(_, z) solve();

    cout << flush;
    _Exit(0);
}