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#include<bits/stdc++.h>
using namespace std;

#define rep(i, a, b) for (int i = (a); i < (b); i++)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()
#define ST first
#define ND second
#define PB push_back
using ll = long long;
using ld = long double;
using pi = pair<int,int>;
using vi = vector<int>;
using vvi = vector<vi>;
using vll = vector<ll>;


#ifdef LOCAL
#define DTP(x, y)                                    \
    auto operator<<(auto &o, auto a)->decltype(y, o) \
    {                                                \
        o << "(";                                    \
        x;                                           \
        return o << ")";                             \
    }
DTP(o << a.first << ", " << a.second, a.second);
DTP(for (auto i : a) o << i << ", ", all(a));
void dump(auto... x) { ((cerr << x << ", "), ...) << '\n'; }
#define debug(x...) cerr << setw(4) << __LINE__ << ":[" #x "]: ", dump(x)
#else
#define debug(...) 0
#endif



void Solve()
{
    int n, m, q;
    cin >> n >> m >> q;
    vector<bitset<50000>> B(n+m);
    rep(i, 1, n+1)
        for(int j=i; j<=n; j+=i)
            B[i-1][j-1]=1;
    rep(i, 0, m){
        int a, x, y;
        cin >> a;
        if(a==1){
            cin >> x >> y;
            --x;
            --y;
            B[n+i]=B[x]|B[y];
        }else if(a==2){
            cin >> x >> y;
            --x;
            --y;
            B[n+i]=B[x]&B[y];
        }else{
            cin >> x;
            --x;
            B[n+i]=B[0]^B[x];
        }
    }
    rep(i, 0, q){
        int x, v;
        cin >> x >> v;
        --x;
        --v;
        if(B[x][v]){
            cout << "TAK\n";
        }else{
            cout << "NIE\n";
        }
    }
    return;
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    int t=1;
    // cin >> t;
    while(t--)
    {
        Solve();
    }
    return 0;
}