#define NDEBUG
#include <algorithm>
#include <cstdio>
#include <cassert>
#include <vector>
const int M = 1000000007;
const long long MM = M;
int N, Q;
int A[500000], B[500000];
int mulimit(int x, int y) {
return std::min(MM, static_cast<long long>(x) * static_cast<long long>(y));
}
int mulmod(int x, int y, bool* overfloat = nullptr) {
long long xy = static_cast<long long>(x) * static_cast<long long>(y);
if (xy >= MM) {
xy %= MM;
if (overfloat) *overfloat = true;
}
return xy;
}
int divrounddown(int x, int y) {
return x / y;
}
struct Funkcja
{
// y = a + b*x
int a = 0;
int b = 1;
bool aOF = false, bOF = false;
void operator*=(const int c)
{
a = mulmod(a, c, &aOF);
b = mulmod(b, c, &bOF);
}
void operator+=(const int c)
{
a += c;
if (a >= M) {
a %= M;
aOF = true;
}
}
int evalmod(const int x, bool& overflow) const
{
long long bx = mulmod(b, x, &overflow);
if (bOF) overflow = true;
long long result = static_cast<long long>(a) + bx;
if (result >= MM) overflow = true;
return result % MM;
}
long long evalimit(const int x) const
{
if (aOF || (x > 0 && bOF)) return M;
int bx = mulimit(b, x);
return std::min(M, a + bx);
}
};
struct Tree
{
int min=0, max=M-1;
int minval=0, maxval=M-1;
Funkcja f;
Tree* left = nullptr;
Tree* right = nullptr;
Tree() {
}
Tree(int min, int max, const Funkcja& f) : min(min), max(max), f(f) {
minval = f.evalimit(min);
maxval = f.evalimit(max);
}
void change(int a, int b)
{
// zawsze i tak przejedziemy całą dziedzinę funkcji
// więc nie ma co się ograniczać
if (left) {
left->change(a, b);
right->change(a, b);
minval = left->minval;
maxval = right->maxval;
} else {
int upto; // dodajemy do upto włącznie, mnożymy od upto+1
if (b == 1) {
upto = M;
} else if (a == 0) {
upto = -1;
} else {
upto = a / (b - 1);
}
if (maxval <= upto) {
// tylko dodajemy
f += a;
minval = std::min(M, minval + a);
maxval = std::min(M, maxval + a);
} else if (upto < minval || f.aOF || f.bOF || upto < f.a) {
// tylko mnożymy
f *= b;
minval = mulimit(minval, b);
maxval = mulimit(maxval, b);
} else {
// dodajemy do upto włącznie
// czyli musimy wyznaczyć odpowiedni x
int upto_x = divrounddown(upto - f.a, f.b);
assert(min <= upto_x);
assert(upto_x+1 <= max);
Funkcja fL(f), fR(f);
fL += a;
fR *= b;
left = new Tree(min, upto_x, fL);
right = new Tree(upto_x+1, max, fR);
minval = left->minval;
maxval = right->maxval;
}
}
}
int evalmod(const int x, bool& overflow) const
{
if (left) {
if (x <= left->max && !overflow) {
return left->evalmod(x, overflow);
} else {
return right->evalmod(x, overflow);
}
} else {
return f.evalmod(x, overflow);
}
}
void wypisz() const
{
if (left) {
printf("[%d-%d]: (values %d-%d)\n", min, max, minval, maxval);
left->wypisz();
right->wypisz();
} else {
printf("[%d-%d]: %d + %d x (values %d-%d)\n", min, max, f.a, f.b, minval, maxval);
}
}
};
void fill(Tree& tree, int l, int r)
{
for (int i=l; i<r; ++i) {
tree.change(A[i], B[i]);
}
}
#define FACTOR 16
#define MAX_L 20
std::vector<Tree> cache[MAX_L+1];
int dawaj(int L, int x, int l, int r, bool& overflow)
{
int upl = (l + FACTOR - 1) / FACTOR;
int upr = r / FACTOR;
if (upl < upr) {
int r1 = upl * FACTOR;
for (int i=l; i<r1; ++i) {
x = cache[L][i].evalmod(x, overflow);
}
x = dawaj(L+1, x, upl, upr, overflow);
int l1 = upr * FACTOR;
for (int i=l1; i<r; ++i) {
x = cache[L][i].evalmod(x, overflow);
}
} else {
for (int i=l; i<r; ++i) {
x = cache[L][i].evalmod(x, overflow);
}
}
return x;
}
int main()
{
scanf("%d%d", &N, &Q);
cache[0].resize(N);
for (int i=0; i<N; ++i) {
scanf("%d%d", &A[i], &B[i]);
cache[0][i].change(A[i], B[i]);
}
int chunk_size = 1;
for (int L=1; L<MAX_L; ++L) {
chunk_size *= FACTOR;
const int chunk_count = N / chunk_size;
if (chunk_count == 0) break;
cache[L].resize(chunk_count);
for (int c=0; c<chunk_count; ++c) {
fill(cache[L][c], c*chunk_size, (c+1)*chunk_size);
}
}
for (int q=0; q<Q; ++q) {
int x, l, r;
scanf("%d%d%d", &x, &l, &r);
bool overflow = false;
x = dawaj(0, x, l, r, overflow);
printf("%d\n", x);
}
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 | #define NDEBUG #include <algorithm> #include <cstdio> #include <cassert> #include <vector> const int M = 1000000007; const long long MM = M; int N, Q; int A[500000], B[500000]; int mulimit(int x, int y) { return std::min(MM, static_cast<long long>(x) * static_cast<long long>(y)); } int mulmod(int x, int y, bool* overfloat = nullptr) { long long xy = static_cast<long long>(x) * static_cast<long long>(y); if (xy >= MM) { xy %= MM; if (overfloat) *overfloat = true; } return xy; } int divrounddown(int x, int y) { return x / y; } struct Funkcja { // y = a + b*x int a = 0; int b = 1; bool aOF = false, bOF = false; void operator*=(const int c) { a = mulmod(a, c, &aOF); b = mulmod(b, c, &bOF); } void operator+=(const int c) { a += c; if (a >= M) { a %= M; aOF = true; } } int evalmod(const int x, bool& overflow) const { long long bx = mulmod(b, x, &overflow); if (bOF) overflow = true; long long result = static_cast<long long>(a) + bx; if (result >= MM) overflow = true; return result % MM; } long long evalimit(const int x) const { if (aOF || (x > 0 && bOF)) return M; int bx = mulimit(b, x); return std::min(M, a + bx); } }; struct Tree { int min=0, max=M-1; int minval=0, maxval=M-1; Funkcja f; Tree* left = nullptr; Tree* right = nullptr; Tree() { } Tree(int min, int max, const Funkcja& f) : min(min), max(max), f(f) { minval = f.evalimit(min); maxval = f.evalimit(max); } void change(int a, int b) { // zawsze i tak przejedziemy całą dziedzinę funkcji // więc nie ma co się ograniczać if (left) { left->change(a, b); right->change(a, b); minval = left->minval; maxval = right->maxval; } else { int upto; // dodajemy do upto włącznie, mnożymy od upto+1 if (b == 1) { upto = M; } else if (a == 0) { upto = -1; } else { upto = a / (b - 1); } if (maxval <= upto) { // tylko dodajemy f += a; minval = std::min(M, minval + a); maxval = std::min(M, maxval + a); } else if (upto < minval || f.aOF || f.bOF || upto < f.a) { // tylko mnożymy f *= b; minval = mulimit(minval, b); maxval = mulimit(maxval, b); } else { // dodajemy do upto włącznie // czyli musimy wyznaczyć odpowiedni x int upto_x = divrounddown(upto - f.a, f.b); assert(min <= upto_x); assert(upto_x+1 <= max); Funkcja fL(f), fR(f); fL += a; fR *= b; left = new Tree(min, upto_x, fL); right = new Tree(upto_x+1, max, fR); minval = left->minval; maxval = right->maxval; } } } int evalmod(const int x, bool& overflow) const { if (left) { if (x <= left->max && !overflow) { return left->evalmod(x, overflow); } else { return right->evalmod(x, overflow); } } else { return f.evalmod(x, overflow); } } void wypisz() const { if (left) { printf("[%d-%d]: (values %d-%d)\n", min, max, minval, maxval); left->wypisz(); right->wypisz(); } else { printf("[%d-%d]: %d + %d x (values %d-%d)\n", min, max, f.a, f.b, minval, maxval); } } }; void fill(Tree& tree, int l, int r) { for (int i=l; i<r; ++i) { tree.change(A[i], B[i]); } } #define FACTOR 16 #define MAX_L 20 std::vector<Tree> cache[MAX_L+1]; int dawaj(int L, int x, int l, int r, bool& overflow) { int upl = (l + FACTOR - 1) / FACTOR; int upr = r / FACTOR; if (upl < upr) { int r1 = upl * FACTOR; for (int i=l; i<r1; ++i) { x = cache[L][i].evalmod(x, overflow); } x = dawaj(L+1, x, upl, upr, overflow); int l1 = upr * FACTOR; for (int i=l1; i<r; ++i) { x = cache[L][i].evalmod(x, overflow); } } else { for (int i=l; i<r; ++i) { x = cache[L][i].evalmod(x, overflow); } } return x; } int main() { scanf("%d%d", &N, &Q); cache[0].resize(N); for (int i=0; i<N; ++i) { scanf("%d%d", &A[i], &B[i]); cache[0][i].change(A[i], B[i]); } int chunk_size = 1; for (int L=1; L<MAX_L; ++L) { chunk_size *= FACTOR; const int chunk_count = N / chunk_size; if (chunk_count == 0) break; cache[L].resize(chunk_count); for (int c=0; c<chunk_count; ++c) { fill(cache[L][c], c*chunk_size, (c+1)*chunk_size); } } for (int q=0; q<Q; ++q) { int x, l, r; scanf("%d%d%d", &x, &l, &r); bool overflow = false; x = dawaj(0, x, l, r, overflow); printf("%d\n", x); } } |
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