#pragma GCC optimize ("Ofast")
#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
#define FOR(i, a, b) for (auto i=(a); i<(b); i++)
#define FORD(i, a, b) for (auto i=(a); i>(b); i--)
#define SZ(x) ((int)(x).size())
#define ITH_BIT(m, i) ((m)>>(i) & 1)
#define PPC(x) __builtin_popcount(x)
using namespace std;
#ifdef DEBUG
#include "debug.h"
#else
#define dbg(...) 0
#endif
template <typename T1, typename T2> inline void remin(T1& a, T2 b) { a = std::min(a, (T1)b); }
template <typename T1, typename T2> inline void remax(T1& a, T2 b) { a = std::max(a, (T1)b); }
const int maxN = 1 << 10, maxTS = maxN * 2, mod = 1'000'000'007;
int T[maxN];
bool done[maxN];
int maxInd(int n)
{
int ret = n;
FOR(i, 0, n)
if (not done[i] and T[ret] < T[i])
ret = i;
return ret;
}
void solve()
{
int n, k, x, res = 0;
scanf ("%d%d", &n, &k);
T[n] = -1;
FOR(i, 0, n)
scanf ("%d", T+i);
while (T[x = maxInd(n)] != -1)
{
for (int i : {x-1, x+1}) if (0 <= i and i < n)
{
int d = std::max(0, T[x] - k - T[i]);
res += d;
T[i] += d;
}
done[x] = true;
}
printf("%d\n", res);
}
int main()
{
int tc = 1;
// scanf ("%d", &tc);
FOR(cid, 1, tc+1)
{
// printf("Case #%d: ", cid);
solve();
}
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 | #pragma GCC optimize ("Ofast") #define _USE_MATH_DEFINES #include <bits/stdc++.h> #define FOR(i, a, b) for (auto i=(a); i<(b); i++) #define FORD(i, a, b) for (auto i=(a); i>(b); i--) #define SZ(x) ((int)(x).size()) #define ITH_BIT(m, i) ((m)>>(i) & 1) #define PPC(x) __builtin_popcount(x) using namespace std; #ifdef DEBUG #include "debug.h" #else #define dbg(...) 0 #endif template <typename T1, typename T2> inline void remin(T1& a, T2 b) { a = std::min(a, (T1)b); } template <typename T1, typename T2> inline void remax(T1& a, T2 b) { a = std::max(a, (T1)b); } const int maxN = 1 << 10, maxTS = maxN * 2, mod = 1'000'000'007; int T[maxN]; bool done[maxN]; int maxInd(int n) { int ret = n; FOR(i, 0, n) if (not done[i] and T[ret] < T[i]) ret = i; return ret; } void solve() { int n, k, x, res = 0; scanf ("%d%d", &n, &k); T[n] = -1; FOR(i, 0, n) scanf ("%d", T+i); while (T[x = maxInd(n)] != -1) { for (int i : {x-1, x+1}) if (0 <= i and i < n) { int d = std::max(0, T[x] - k - T[i]); res += d; T[i] += d; } done[x] = true; } printf("%d\n", res); } int main() { int tc = 1; // scanf ("%d", &tc); FOR(cid, 1, tc+1) { // printf("Case #%d: ", cid); solve(); } return 0; } |
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