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// Arti1990, II UWr

#include <bits/stdc++.h>

#define forr(i, n)                  for(int i=0; i<n; i++)
#define FOREACH(iter, coll)         for(auto iter = coll.begin(); iter != coll.end(); ++iter)
#define FOREACHR(iter, coll)        for(auto iter = coll.rbegin(); iter != coll.rend(); ++iter)
#define lbound(P,K,FUN)             ({auto SSS=P, PPP = P-1, KKK=(K)+1; while(PPP+1!=KKK) {SSS = (PPP+(KKK-PPP)/2); if(FUN(SSS)) KKK = SSS; else PPP = SSS;} PPP;})
#define testy()                     int _tests; cin>>_tests; FOR(_test, 1, _tests)
#define CLEAR(tab)                  memset(tab, 0, sizeof(tab))
#define CONTAIN(el, coll)           (coll.find(el) != coll.end())
#define FOR(i, a, b)                for(int i=a; i<=b; i++)
#define FORD(i, a, b)               for(int i=a; i>=b; i--)
#define MP                          make_pair
#define PB                          push_back
#define ff                          first
#define ss                          second
#define deb(X)                      X;
#define SIZE(coll) 					((int)coll.size())
//#define cerr if(0) cerr

#define M 1000000007
#define INF 1000000007LL

using namespace std;

int n, t;
string name, str, pkn = "PKN";
char ja, on;
string ja_kod, on_kod;
int bije[3][3] = {{0, 1, -1}, {-1, 0, 1}, {1, -1, 0}};
int numer[128];
int bits[1007][5007];

string zakoduj(int nr)
{
    string s = "";
    forr(i, 6)
    {
        s += pkn[nr%3];
        nr /= 3;
    }
    return s;
}

int odkoduj(string s)
{
    int nr = 0;
    forr(i, 6)
        nr = nr * 3 + numer[s[5-i]];
    return nr;
}

int policz(string s, int nr)
{
    forr(i, n)
        s[i] ^= bits[nr][i];
    int ile = 0;
    forr(i, n)
        ile += s[i] == '1';
    return ile;
}

void run()
{
    cin >> str;
    str += "0000000000";
    ja_kod = on_kod = "";

    int nr = 0, best = n+1;
    forr(i, 3*3*3*3*3*3)
    {
        int x = policz(str, i);
        if(x < best)
        {
            best = x;
            nr = i;
        }
    }

    //cerr << "best: " << best << '\n';

    ja_kod = zakoduj(nr);

    forr(i, n)
        str[i] ^= bits[nr][i];

    int pkt = 0;
    int ile = 0, ile_kod = 0;
    string res = "";
    //cerr << name + " ma ciag " + str + '\n';
    while(ile < n || res.size() < n)
    {
        if(pkt != 0)
        {
            ja = (pkt == 1 ? 'K' : 'P');
        }
        else
        {
            if(ile_kod < 6)
            {
                ja = ja_kod[ile_kod];
            }
            else if(ile >= n)
                ja = 'P';
            else if(str[ile] == '1') // '1'
            {
                ja = 'P';
                ile++;
            }
            else if(str[ile+1] == '0') // '00'
            {
                ja = 'K';
                ile += 2;
            }
            else if(str[ile+1] == '1') // '01'
            {
                ja = 'N';
                ile += 2;
            }
        }

        cout << ja << endl;
        cout.flush();
        cin >> on;
        //cerr << name + " mowi " + ja + ", dostaje " + on + '\n';

        if(pkt == 0)
        {
            if(ile_kod < 6)
            {
                on_kod += on;
                ile_kod++;
            }
            else if(on == 'P')
                res += "1";
            else if(on == 'K')
                res += "00";
            else if(on == 'N')
                res += "01";
        }

        pkt += bije[numer[ja]][numer[on]];
        //cerr << name + " ma ile " + to_string(ile) + ", pkt: " + to_string(pkt) + '\n';
    }
    
    int numer = odkoduj(on_kod);
    //cerr << name + " ma numer " + to_string(numer) + '\n';
    
    forr(i, n)
        res[i] ^= bits[numer][i];

    cout << "! " << res.substr(0, n) << endl;
    cout.flush();
    //cerr << name + " znalazl ciag " + res + '\n';
}

int solve()
{
    forr(i, 3)
        numer[pkn[i]] = i;

    forr(i, 1003)
        forr(j, 5004)
            bits[i][j] = rand() % 2;

    cin >> name;
    cin >> n >> t;

    forr(tt, t)
    {
        run();
    }

    return 0;
}

int main()
{
    std::ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    srand(1990);

    solve();

    return 0;
}