//Kazda fala wnosi k burszytnow, wiec k musi dzielic ich sume
#include <iostream>
#include <vector>
#include <algorithm>
#include <numeric>
using namespace std;
typedef long long LL;
typedef vector<LL> VI;
bool check(const VI& a, int n, int k)
{
VI delta(n + 2, 0);
LL cur = 0;
int lastStart = n - k + 1;
for (int i = 1; i <= n; ++i)
{
cur += delta[i];
LL needed = a[i] - cur;
if (i <= lastStart)
{
if (needed < 0) return false;
cur += needed;
delta[i + k] -= needed;
}
else if (needed != 0) return false;
}
return true;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
int n; cin >> n;
VI a(n + 1);
for (int i = 1; i <= n; ++i) cin >> a[i];
LL S = accumulate(a.begin() + 1, a.end(), 0LL);
VI divisors;
for (LL d = 1; d * d <= S; ++d)
{
if (S % d != 0) continue;
if (d <= n) divisors.push_back(d);
LL other = S / d;
if (other != d && other <= n) divisors.push_back(other);
}
sort(divisors.begin(), divisors.end(), greater<int>());
for (int k : divisors) { if (check(a, n, k)) { cout << k << endl; break; }}
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 | //Kazda fala wnosi k burszytnow, wiec k musi dzielic ich sume #include <iostream> #include <vector> #include <algorithm> #include <numeric> using namespace std; typedef long long LL; typedef vector<LL> VI; bool check(const VI& a, int n, int k) { VI delta(n + 2, 0); LL cur = 0; int lastStart = n - k + 1; for (int i = 1; i <= n; ++i) { cur += delta[i]; LL needed = a[i] - cur; if (i <= lastStart) { if (needed < 0) return false; cur += needed; delta[i + k] -= needed; } else if (needed != 0) return false; } return true; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; VI a(n + 1); for (int i = 1; i <= n; ++i) cin >> a[i]; LL S = accumulate(a.begin() + 1, a.end(), 0LL); VI divisors; for (LL d = 1; d * d <= S; ++d) { if (S % d != 0) continue; if (d <= n) divisors.push_back(d); LL other = S / d; if (other != d && other <= n) divisors.push_back(other); } sort(divisors.begin(), divisors.end(), greater<int>()); for (int k : divisors) { if (check(a, n, k)) { cout << k << endl; break; }} return 0; } |
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