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use std::collections::HashMap;

macro_rules! input {
    (from $iter:expr, $($r:tt)*) => {
        input_inner!{$iter, $($r)*}
    };
    (source = $s:expr, $($r:tt)*) => {
        let mut iter = $s.split_whitespace();
        input_inner!{iter, $($r)*}
    };
    ($($r:tt)*) => {
        let s = {
            use std::io::Read;
            let mut s = String::new();
            std::io::stdin().read_to_string(&mut s).unwrap();
            s
        };
        let mut iter = s.split_whitespace();
        input_inner!{iter, $($r)*}
    };
}

macro_rules! input_inner {
    ($iter:expr) => {};
    ($iter:expr, ) => {};

    ($iter:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($iter, $t);
        input_inner!{$iter $($r)*}
    };
}

macro_rules! read_value {
    ($iter:expr, ( $($t:tt),* )) => {
        ( $(read_value!($iter, $t)),* )
    };

    ($iter:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()
    };

    ($iter:expr, chars) => {
        read_value!($iter, String).chars().collect::<Vec<char>>()
    };

    ($iter:expr, usize1) => {
        read_value!($iter, usize) - 1
    };

    ($iter:expr, $t:ty) => {
        $iter.next().unwrap().parse::<$t>().expect("Parse error")
    };
}

fn solve(n: usize, k: usize, hardcodes: &HashMap<(usize, usize), &str>) -> String {
    if k < 4 {
        if let Some(result) = hardcodes.get(&(n, k)) {
            return result.to_string();
        } else {
            return "NIE".to_string();
        }
    }

    (["A".repeat(k), "PAPPAA".repeat(n / 5)].join(""))[..n].to_string()
}

fn main() {
    let s = {
        use std::io::Read;
        let mut s = String::new();
        std::io::stdin().read_to_string(&mut s).unwrap();
        s
    };
    let mut iter = s.split_whitespace();
    let hardcodes = HashMap::from([
        ((0, 0), ""),
        ((1, 1), "P"),
        ((2, 2), "PP"),
        ((2, 1), "PA"),
        ((3, 3), "PPP"),
        ((3, 2), "PPA"),
        ((4, 4), "PPPP"),
        ((4, 3), "PPPA"),
        ((4, 2), "PPAA"),
        ((5, 5), "PPPPP"),
        ((5, 4), "PPPPA"),
        ((5, 3), "PPPAP"),
        ((6, 6), "PPPPPP"),
        ((6, 5), "PPPPPA"),
        ((6, 4), "PPPPAP"),
        ((6, 3), "PPPAPA"),
        ((7, 7), "PPPPPPP"),
        ((7, 6), "PPPPPPA"),
        ((7, 5), "PPPPPAP"),
        ((7, 4), "PPPPAPA"),
        ((7, 3), "PPPAPAA"),
        ((8, 8), "PPPPPPPP"),
        ((8, 7), "PPPPPPPA"),
        ((8, 6), "PPPPPPAP"),
        ((8, 5), "PPPPPAPP"),
        ((8, 4), "PPPPAPAA"),
        ((8, 3), "PPPAPAAA"),
    ]);

    input! {
        from iter,
        t: usize,
    }

    for _ in 0..t {
        input! {
            from iter,
            n: usize,
            k: usize,
        }

        println!("{}", solve(n, k, &hardcodes));
    }
}