/************************************************************************* * Zadanie: Iloczyn * * Zlozonosc czasowa: O(t log n log log n) * * Wynik: --/10 * *************************************************************************/ #include <iostream> #include <vector> #include <algorithm> using namespace std; #define FOR(x,b,e) for(int x=b; x<=e; ++x) /*************************************************************************/ int main() { ios_base::sync_with_stdio(0); int F[44] = {1, 1}; FOR(i,2,43) F[i] = F[i-1] + F[i-2]; int t; cin >> t; FOR(c,1,t) { int n; cin >> n; bool ans = (n == 0); for(int i = 1; F[i]*F[i] <= n; ++i) if (n%F[i] == 0 && binary_search(F,F+44,(n/F[i]))) { ans = 1; break; } cout << ((ans)? "TAK" : "NIE") << '\n'; } return 0; } /*************************************************************************/
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 | /************************************************************************* * Zadanie: Iloczyn * * Zlozonosc czasowa: O(t log n log log n) * * Wynik: --/10 * *************************************************************************/ #include <iostream> #include <vector> #include <algorithm> using namespace std; #define FOR(x,b,e) for(int x=b; x<=e; ++x) /*************************************************************************/ int main() { ios_base::sync_with_stdio(0); int F[44] = {1, 1}; FOR(i,2,43) F[i] = F[i-1] + F[i-2]; int t; cin >> t; FOR(c,1,t) { int n; cin >> n; bool ans = (n == 0); for(int i = 1; F[i]*F[i] <= n; ++i) if (n%F[i] == 0 && binary_search(F,F+44,(n/F[i]))) { ans = 1; break; } cout << ((ans)? "TAK" : "NIE") << '\n'; } return 0; } /*************************************************************************/ |