#include <stdio.h> using namespace std; int main(int argc, char** argv) { int amountOfInputNumbers; /* It is faster to create constant table of Fibonnaci numbers < 10^9, than to calculate Fibonacci numbers every time */ int fibonacciFrom2to44[43] = { 1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946, 17711,28657,46368,75025,121393,196418,317811,514229,832040,1346269, 2178309,3524578,5702887,9227465,14930352,24157817,39088169,63245986, 102334155,165580141,267914296,433494437,701408733 }; scanf("%d",&amountOfInputNumbers); for(int i=0; i<amountOfInputNumbers; i++){ int currentNumber; scanf("%d",¤tNumber); if(currentNumber != 0){ int smallerIndex = 0; int biggerIndex = 42; int multiplication; do{ multiplication = fibonacciFrom2to44[smallerIndex] * fibonacciFrom2to44[biggerIndex]; if(multiplication > currentNumber) biggerIndex --; else if (multiplication < currentNumber) smallerIndex ++; else printf("TAK\n"); } while ( (smallerIndex <= biggerIndex) && (multiplication != currentNumber) ); if(multiplication != currentNumber){ printf("NIE\n"); } } else printf("TAK\n"); } return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 | #include <stdio.h> using namespace std; int main(int argc, char** argv) { int amountOfInputNumbers; /* It is faster to create constant table of Fibonnaci numbers < 10^9, than to calculate Fibonacci numbers every time */ int fibonacciFrom2to44[43] = { 1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946, 17711,28657,46368,75025,121393,196418,317811,514229,832040,1346269, 2178309,3524578,5702887,9227465,14930352,24157817,39088169,63245986, 102334155,165580141,267914296,433494437,701408733 }; scanf("%d",&amountOfInputNumbers); for(int i=0; i<amountOfInputNumbers; i++){ int currentNumber; scanf("%d",¤tNumber); if(currentNumber != 0){ int smallerIndex = 0; int biggerIndex = 42; int multiplication; do{ multiplication = fibonacciFrom2to44[smallerIndex] * fibonacciFrom2to44[biggerIndex]; if(multiplication > currentNumber) biggerIndex --; else if (multiplication < currentNumber) smallerIndex ++; else printf("TAK\n"); } while ( (smallerIndex <= biggerIndex) && (multiplication != currentNumber) ); if(multiplication != currentNumber){ printf("NIE\n"); } } else printf("TAK\n"); } return 0; } |