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///*** Naglowki Piotra Stanczyka

#include <iostream>
#include <cstdio>
#include <vector>
#include <cmath>
#include <algorithm>
#include <ctime>
#include <fstream>

using namespace std;
typedef vector<int> VI;
typedef long long LL;

#define FOR(x, b, e) for(int x=b; x<=(e); ++x)
#define FORD(x, b, e) for(int x=b; x>=(e); x--)
#define REP(x, n) for(int x=0; x<(n); ++x)
#define VAR(v,n) typeof(n) v=(n)
#define ALL(c) c.begin(),c.end()
#define SIZE(x) (int)x.size()
#define FOREACH(i,c) for(VAR(i,(c).begin());i!=(c).end();++i)
#define PB push_back
#define ST first
#define ND second

const int size = 100000;
const int INF = 1000000300;

struct H
{
    int id1, id2, h;
};

struct P
{
    int x, h, id;
};

vector <P> perm1, perm2;
vector <H> heights, T(size);

bool sortPreferencesH(H x, H y)
{
    return x.h < y.h || (x.h == y.h && x.id1 < y.id1);
}

bool sortPreferencesP(P a, P b)
{
    return a.x < b.x ||(a.x == b.x && a.h < b.h);
}

int main()
{
    ios_base::sync_with_stdio(0);

    int t, n, w, x1, x2, y1, y2;
    P pr;
    H wys;

    cin>>t;

    REP(x, t)
    {
        cin>>n>>w;

        perm1.clear();
        perm2.clear();
        heights.clear();

        FOR(i, 1, n)
        {
            cin>>x1>>y1>>x2>>y2;

            //P.x = min(x1, x2);
            //P.h = abs()

            if(x1 < x2)pr.x = x1;
            else pr.x = x2;
            if(y1 < y2)pr.h = y2-y1;
            else pr.h = y1-y2;

            pr.id = i;

            perm1.PB(pr);
        }
        FOR(i, 1, n)
        {
            cin>>x1>>y1>>x2>>y2;

            //P.x = min(x1, x2);
            //P.h = abs()

            if(x1 < x2)pr.x = x1;
            else pr.x = x2;
            if(y1 < y2)pr.h = y2-y1;
            else pr.h = y1-y2;

            pr.id = i;

            T[i].h = pr.h;

            perm2.PB(pr);
        }

        sort(perm1.begin(), perm1.end(), sortPreferencesP);
        sort(perm2.begin(), perm2.end(), sortPreferencesP);

        /*cout<<"sorted perm1 id x h:\n";
        FOREACH(i, perm1)cout<<i->id<<' '<<i->x<<' '<<i->h<<endl;
        cout<<"sorted perm2 id x h:\n";
        FOREACH(i, perm2)cout<<i->id<<' '<<i->x<<' '<<i->h<<endl;*/

        FOR(i, 0, n-1)T[perm1[i].id].id1 = i;
        FOR(i, 0, n-1)T[perm2[i].id].id2 = i;

        //cout<<"T i id1 id2 h:\n";
        //FOR(i, 1, n)cout<<i<<' '<<T[i].id1<<' '<<T[i].id2<<' '<<T[i].h<<endl;

        bool check = true;

        FOR(i, 1, n)FOR(j, 1, n)
        {
            if((T[i].id1-T[j].id1)*(T[i].id2-T[j].id2) < 0 &&
               T[i].h+T[j].h > w)
            {
                check = false;
                break;
            }
        }

        /*FOR(i, 1, n)
        {
            heights.PB(T[i]);
        }

        sort(heights.begin(), heights.end(), sortPreferencesH);

        cout<<"sorted heights\nid1 id2 h:\n";
        FOREACH(i, heights)cout<<i->id1<<' '<<i->id2<<' '<<i->h<<endl;

        //int k, l;

        FORD(i, n-1, 1)
        {
            //k = heights[i].id1;
            //l = heights[i].id2;

            if(heights[i].h + heights[i-1].h > w &&
               (heights[i].id1-heights[i-1].id1)*(heights[i].id2-heights[i-1].id2) < 0)
            {
                check = false;
                break;
            }
        }*/

        if(check)cout<<"TAK\n";
        else cout<<"NIE\n";
    }

    return 0;
}