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// Artur Kraska, II UWr

#include <algorithm>
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <vector>
#include <cmath>
#include <list>
#include <set>
#include <map>

#define forr(i, n)                  for(int i=0; i<n; i++)
#define FOREACH(iter, coll)         for(typeof(coll.begin()) iter = coll.begin(); iter != coll.end(); ++iter)
#define FOREACHR(iter, coll)        for(typeof(coll.rbegin()) iter = coll.rbegin(); iter != coll.rend(); ++iter)
#define lbound(P,R,PRED)            ({typeof(P) X=P,RRR=(R), PPP = P; while(PPP<RRR) {X = (PPP+(RRR-PPP)/2); if(PRED) RRR = X; else PPP = X+1;} PPP;})
#define testy()                     int _tests; scanf("%d", &_tests); FOR(_test, 1, _tests)
#define CLEAR(tab)                  memset(tab, 0, sizeof(tab))
#define CONTAIN(el, coll)           (coll.find(el) != coll.end())
#define FOR(i, a, b)                for(int i=a; i<=b; i++)
#define FORD(i, a, b)               for(int i=a; i>=b; i--)
#define MP                          make_pair
#define PB                          push_back
#define deb(X)                      X;

#define M 1000000007
#define INF 1000000000000000007ll

using namespace std;

//int tab[107], res[107][10007];
//long long il[107][10007];

long long n, k;
vector <vector <long long> > v;
int d[1000007], S = 1<<18;
/*
void dzialaj(int poz)
{
    if(poz == n)
    {
        int il = 0;
        forr(i, n)
            FOR(j, i+1, n-1)
                if(tab[i] > tab[j])
                    il++;
        res[n][il]++;
    }
    else
    {
        FOR(i, poz, n-1)
        {
            swap(tab[i], tab[poz]);
            dzialaj(poz+1);
            swap(tab[i], tab[poz]);
        }
    }
}
*/
long long ile(long long n, long long k)
{
    if(k > n*(n-1)/2)
        return 0;
    if(k < v[n].size())
        return v[n][k];
    if(n*(n-1)/2 - k < v[n].size())
        return v[n][n*(n-1)/2 - k];
    return INF;
}

int znajdz_i_wez(int poz)
{
//    cout << "szuka " << poz << endl;
    int nr = 1;
    while(nr < S)
    {
        d[nr]--;
        if(d[nr*2] < poz)
        {
            poz -= d[nr*2];
            nr = nr*2+1;
        }
        else
            nr *= 2;
    }
    d[nr]--;
//    cout << "znalazl " << nr-S+1 << endl;
    return nr-S+1;
}

int main()
{
/*    FOR(x, 1, 10)
    {
        n = x;
        forr(i, n)
            tab[i] = i+1;
        dzialaj(0);
        FOR(i, 0, n*(n-1)/4)
            cout << "res[" << n << "][" << i << "] = " << res[n][i] << endl;
    }*/
    vector <long long> v0;
    v0.PB(1);
    v.PB(v0);
    //il[0][0] = 1;
    FOR(x, 1, 250003)
    {
        vector <long long> prev = v.back(), now;
        //il[x][0] = il[x][x*(x-1)/2] = 1;
        now.PB(1);

        FOR(i, 1, max(10, x*(x-1)/2))
        {
            //il[x][i] = il[x][i-1] + il[x-1][i] - (i >= x ? il[x-1][i-x] : 0);
            now.PB(now[i-1] + (prev.size() > i ? prev[i] : 0) - (prev.size() > i-x && i-x >= 0 ? prev[i-x] : 0));
            if(now.back() >= INF)
            {
                now[i] = INF;
                break;
            }
            //il[x][x*(x-1)/2-i] = il[x][i];
        }
        v.PB(now);
    }
    FOR(i, 0, -250000)
    {
        cout << i << ":";
        forr(j, v[i].size())
        {
            cout << "  " << v[i][j];
        }
        cout << endl;
    }

    scanf("%lld %lld", &n, &k);
    long long inw = n*(n-1)/4;
    if(n*(n-1)/2 %2 != 0 || k > ile(n, inw))
    {
        printf("NIE\n");
        return 0;
    }
    printf("TAK\n");
    k--;

    //list <long long> l;
    //FOR(i, 1, n)
     //   l.PB(i);

    FOR(i, 0, n)
        d[i+S] = 1;
    FORD(i, S-1, 1)
        d[i] = d[i*2] + d[i*2+1];

    while(n > 0)
    {
        int nr = 0;
        //cout << "przed " << n << endl;
        if(inw > (n-1)*(n-2)/2)
        {
            int x = inw - (n-1)*(n-2)/2;
            inw -= x;
            nr += x;
        }
        while(ile(n-1, inw) <= k)
        {
            nr++;
            k -= ile(n-1, inw);
            inw--;
        }
        //cout << "po" << endl;
        int elem = znajdz_i_wez(nr+1);
        /*list <long long>::iterator it = l.begin();
        while(nr > 0)
        {
            it++;
            nr--;
        }*/
        printf("%d ", elem);
        //l.erase(it);
        n--;
    }
    printf("\n");

    return 0;
}