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106 | #include <bits/stdc++.h>
#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define FORD(i, a, b) for(int i = (a); i >= (b); --i)
#define VAR(v, i) __typeof(i) v=(i)
#define FORE(i, c) for(VAR(i, (c).begin()); i != (c).end(); ++i)
#define all(v) (v).begin(),(v).end()
#define PII pair<int,int>
#define st first
#define nd second
#define pb push_back
#define lint long long int
#define VI vector<int>
#define debug(x) {cout <<#x <<" = " <<x <<endl; }
#define debug2(x,y) {cerr <<#x <<" = " <<x << ", "<<#y<<" = "<< y <<endl; }
#define debug3(x,y,z) {cerr <<#x <<" = " <<x << ", "<<#y<<" = "<< y << ", " << #z << " = " << z <<endl; }
#define debugv(x) {{cout <<#x <<" = "; FORE(itt, (x)) cerr <<*itt <<", "; cerr <<endl; }}
#define debugt(t,n) {{cerr <<#t <<" = "; FOR(it,0,(n)) cerr <<t[it] <<", "; cerr <<endl; }}
#define make( x) int (x); scanf("%d",&(x));
#define make2( x, y) int (x), (y); scanf("%d%d",&(x),&(y));
#define make3(x, y, z) int (x), (y), (z); scanf("%d%d%d",&(x),&(y),&(z));
#define make4(x, y, z, t) int (x), (y), (z), (t); scanf("%d%d%d%d",&(x),&(y),&(z),&(t));
#define makev(v,n) VI (v); FOR(i,0,(n)) { make(a); (v).pb(a);}
#define IOS ios_base::sync_with_stdio(0)
#define HEAP priority_queue
#define read( x) scanf("%d",&(x));
#define read2( x, y) scanf("%d%d",&(x),&(y));
#define read3(x, y, z) scanf("%d%d%d",&(x),&(y),&(z));
#define read4(x, y, z, t) scanf("%d%d%d%d",&(x),&(y),&(z),&(t));
#define readv(v,n) FOR(i,0,(n)) { make(a); (v).pb(a);}
#define jeb() fflush(stdout);
using namespace std;
int n;
lint m;
vector<lint> v;
lint pref[205];
lint dp[205][205][62];
lint dp2[205][62];
lint INF = 1e9*1LL*1e9;
lint sum(int i, int j) {
if (i > j) return 0;
return pref[j] - ((i==0)? 0 : pref[i-1]);
}
// odpowiedz dla przedzialu [i,j)
// z wagami [0,2^k-1]
lint rob(int i, int j, int k) {
if (dp[i][j][k] != -INF-1) return dp[i][j][k];
if (i == j) return 0;
if (j-i > (1LL<<k)) return -INF;
if (k == 0) return 0;
lint best = -INF;
FOR(s,i,j+1) {
best = max(best, sum(s,j-1) + rob(i,s,k-1) + rob(s,j,k-1));
}
dp[i][j][k] = best;
return best;
}
// odpowiedz dla przedzialu [i, n)
// z wagami [0,m&(2^k-1)]
lint rob2(int i, int k) {
if (dp2[i][k] != -INF -1) return dp2[i][k];
if (i == n) return 0;
lint up = m & ((1LL<<k) - 1);
if (up+1 < n-i) return -INF;
if (up == 0) return 0;
if ((m & (1LL<<(k-1))) == 0) {
return rob2(i, k-1);
}
lint best = -INF;
FOR(s,i,n+1) {
best = max(best, sum(s,n-1) + rob(i,s,k-1) + rob2(s,k-1));
}
dp2[i][k] = best;
return best;
}
void brut() {
int u = 60;
while (u > 0 && (1LL<<u) > m) u--;
u++;
FOR(i,0,n+1) FOR(j,i,n+1) FOR(k,0,61) dp[i][j][k] = -INF-1;
FOR(i,0,n+1) FOR(k,0,61) dp2[i][k] = -INF-1;
printf("%lld\n", rob2(0,u));
}
int main() {
read(n);
scanf("%lld", &m);
FOR(i,0,n) {
lint a; scanf("%lld", &a);
v.pb(a);
}
pref[0] = v[0];
FOR(i,1,n) pref[i] = pref[i-1] + v[i];
brut();
}
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