// Artur Kraska, II UWr
#include <bits/stdc++.h>
#define forr(i, n) for(int i=0; i<n; i++)
#define FOREACH(iter, coll) for(typeof(coll.begin()) iter = coll.begin(); iter != coll.end(); ++iter)
#define FOREACHR(iter, coll) for(typeof(coll.rbegin()) iter = coll.rbegin(); iter != coll.rend(); ++iter)
#define lbound(P,R,PRED) ({typeof(P) X=P,RRR=(R), PPP = P; while(PPP<RRR) {X = (PPP+(RRR-PPP)/2); if(PRED) RRR = X; else PPP = X+1;} PPP;})
#define testy() int _tests; scanf("%d", &_tests); FOR(_test, 1, _tests)
#define CLEAR(tab) memset(tab, 0, sizeof(tab))
#define CONTAIN(el, coll) (coll.find(el) != coll.end())
#define FOR(i, a, b) for(int i=a; i<=b; i++)
#define FORD(i, a, b) for(int i=a; i>=b; i--)
#define MP make_pair
#define PB push_back
#define deb(X) X;
#define M 1000000007
#define INF 2000000000000000007LL
using namespace std;
int n;
long long tab[66][207][207], m, a, t[207], sum[207], res[207];
long long suma(int p, int k)
{
return sum[k] - sum[p-1];
}
int main()
{
/*forr(i, 307)
{
if(i%8 == 0)
cout << endl << i << " -> ";
cout << __builtin_popcount(i) << " ";
}*/
scanf("%d %lld", &n, &m);
m++;
FOR(i, 1, n)
{
scanf("%lld", &t[i]);
sum[i] = t[i] + sum[i-1];
}
long long ile = 0, m2 = m;
while(m2 > 0)
{
m2 /= 2;
ile++;
}
ile--; // sprawdzic m=0
FOR(i, 1, n)
{
tab[0][i][i] = 0;
FOR(j, i+1, n)
tab[0][i][j] = -INF;
}
//cout << ile << endl;
FOR(d, 1, ile)
{
FOR(i, 1, n)
{
tab[d][i][i-1] = 0;
FOR(j, i, n)
{
tab[d][i][j] = -INF;
FOR(k, i-1, j)
{
tab[d][i][j] = max(tab[d][i][j], tab[d-1][i][k] + tab[d-1][k+1][j] + suma(k+1, j));
}
//cout << "tab[" << i << "][" << j << "][" << d << "] = " << tab[i][j][d] << endl;
}
}
tab[d][n+1][n] = 0;
}
FOR(i, 1, n)
res[i] = -INF;
res[n+1] = 0;
FOR(d, 0, ile)
{
if((m & (1LL<<d)) == 0)
continue;
FOR(i, 1, n)
{
res[i] = max(res[i], res[i] + suma(i, n));
res[i] = max(tab[d][i][n], res[i]);
FOR(k, i, n)
{
res[i] = max(res[i], tab[d][i][k] + res[k+1] + suma(k+1, n));
}
//cout << "res[" << i << "][" << d << "] = " << res[i] << endl;
}
}
printf("%lld\n", res[1]);
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 | // Artur Kraska, II UWr #include <bits/stdc++.h> #define forr(i, n) for(int i=0; i<n; i++) #define FOREACH(iter, coll) for(typeof(coll.begin()) iter = coll.begin(); iter != coll.end(); ++iter) #define FOREACHR(iter, coll) for(typeof(coll.rbegin()) iter = coll.rbegin(); iter != coll.rend(); ++iter) #define lbound(P,R,PRED) ({typeof(P) X=P,RRR=(R), PPP = P; while(PPP<RRR) {X = (PPP+(RRR-PPP)/2); if(PRED) RRR = X; else PPP = X+1;} PPP;}) #define testy() int _tests; scanf("%d", &_tests); FOR(_test, 1, _tests) #define CLEAR(tab) memset(tab, 0, sizeof(tab)) #define CONTAIN(el, coll) (coll.find(el) != coll.end()) #define FOR(i, a, b) for(int i=a; i<=b; i++) #define FORD(i, a, b) for(int i=a; i>=b; i--) #define MP make_pair #define PB push_back #define deb(X) X; #define M 1000000007 #define INF 2000000000000000007LL using namespace std; int n; long long tab[66][207][207], m, a, t[207], sum[207], res[207]; long long suma(int p, int k) { return sum[k] - sum[p-1]; } int main() { /*forr(i, 307) { if(i%8 == 0) cout << endl << i << " -> "; cout << __builtin_popcount(i) << " "; }*/ scanf("%d %lld", &n, &m); m++; FOR(i, 1, n) { scanf("%lld", &t[i]); sum[i] = t[i] + sum[i-1]; } long long ile = 0, m2 = m; while(m2 > 0) { m2 /= 2; ile++; } ile--; // sprawdzic m=0 FOR(i, 1, n) { tab[0][i][i] = 0; FOR(j, i+1, n) tab[0][i][j] = -INF; } //cout << ile << endl; FOR(d, 1, ile) { FOR(i, 1, n) { tab[d][i][i-1] = 0; FOR(j, i, n) { tab[d][i][j] = -INF; FOR(k, i-1, j) { tab[d][i][j] = max(tab[d][i][j], tab[d-1][i][k] + tab[d-1][k+1][j] + suma(k+1, j)); } //cout << "tab[" << i << "][" << j << "][" << d << "] = " << tab[i][j][d] << endl; } } tab[d][n+1][n] = 0; } FOR(i, 1, n) res[i] = -INF; res[n+1] = 0; FOR(d, 0, ile) { if((m & (1LL<<d)) == 0) continue; FOR(i, 1, n) { res[i] = max(res[i], res[i] + suma(i, n)); res[i] = max(tab[d][i][n], res[i]); FOR(k, i, n) { res[i] = max(res[i], tab[d][i][k] + res[k+1] + suma(k+1, n)); } //cout << "res[" << i << "][" << d << "] = " << res[i] << endl; } } printf("%lld\n", res[1]); return 0; } |
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