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104 | #include <bits/stdc++.h>
using namespace std;
typedef unsigned uint;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ldbl;
typedef pair<int, int> pii;
typedef pair<uint, uint> puu;
typedef pair<ll, ll> pll;
typedef pair<ull, ull> pull;
typedef pair<double, double> pdd;
typedef vector<int> vi;
typedef vector<uint> vu;
typedef vector<ll> vll;
typedef vector<ull> vull;
typedef vector<pii> vpii;
typedef vector<puu> vpuu;
typedef vector<pll> vpll;
typedef vector<pull> vpull;
typedef vector<string> vstr;
typedef vector<double> vdbl;
typedef vector<ldbl> vldbl;
#define pb push_back
#define ppb pop_back
#define pfr push_front
#define ppfr pop_front
#define emp emplace
#define empb emplace_back
#define be begin
#define rbe rbegin
#define all(x) (x).be(), (x).end()
#define rall(x) (x).rbe(), (x).rend()
#define fir first
#define sec second
#define mkp make_pair
#define brif(cond) if (cond) break
#define ctif(cond) if (cond) continue
#define retif(cond) if (cond) return
void canhazfast() {ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);}
template<typename T> T gcd(T a, T b) {return b ? gcd(b, a%b) : a;}
template<typename T> T extgcd(T a, T b, T &x, T &y)
{
T x0 = 1, y0 = 0, x1 = 0, y1 = 1;
while (b) {
T q = a/b; a %= b; swap(a, b);
x0 -= q*x1; swap(x0, x1);
y0 -= q*y1; swap(y0, y1);
}
x = x0; y = y0; return a;
}
int ctz(uint x) {return __builtin_ctz(x);}
int ctzll(ull x) {return __builtin_ctzll(x);}
int clz(uint x) {return __builtin_clz(x);}
int clzll(ull x) {return __builtin_clzll(x);}
int popcnt(uint x) {return __builtin_popcount(x);}
int popcntll(ull x) {return __builtin_popcountll(x);}
int bsr(uint x) {return 31^clz(x);}
int bsrll(ull x) {return 63^clzll(x);}
#define N 100016
#define nope cout << "NIE\n", void()
pii pa[N], pb[N];
void solve()
{
int n;
ll sum = 0;
cin >> n;
for (int i = 0; i < n; ++i) {
int c;
cin >> c >> pa[i].fir >> pb[i].fir;
pa[i].sec = pb[i].sec = c;
}
sort(pa, pa+n);
sort(pb, pb+n);
retif(pb[0].fir < pa[0].fir) nope;
retif(pb[n-1].fir > pa[n-1].fir) nope;
for (int i = 0, j = 0; i < n && j < n; ) {
int len = min(pa[i].sec, pb[j].sec);
ll diff = ll(pb[j].fir-pa[i].fir)*len;
sum += diff;
retif(sum < 0) nope;
if (!(pa[i].sec -= len)) ++i;
if (!(pb[j].sec -= len)) ++j;
}
retif(sum != 0) nope;
cout << "TAK\n";
}
int main()
{
canhazfast();
int t;
cin >> t;
for (; t; --t) solve();
return 0;
}
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