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#include <iostream>
#include <algorithm>
#define ff first
#define ss second
using namespace std;

int t,n;
int c[100007];
pair<int,int> a[100007], b[100007];
long long sa,sb,dplus,dminus;
bool ok;

int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cin>>t;
    for (int ii=0; ii<t; ii++)
    {
        cin>>n;
        for (int i=0; i<n; i++)
        {
            cin>>c[i]>>a[i].ff>>b[i].ff;
            a[i].ss=c[i];
            b[i].ss=c[i];
            sa+=(long long)c[i]*(long long)a[i].ff;
            sb+=(long long)c[i]*(long long)b[i].ff;
            if (a[i].ff>b[i].ff)
                dminus+=(long long)(a[i].ff-b[i].ff)*(long long)c[i];
            else
                dplus+=(long long)(b[i].ff-a[i].ff)*(long long)c[i];
        }
        if ( sa==sb && dplus==dminus )
        {
            sort(a,a+n);
            sort(b,b+n);
            ok=1;
            for (int i=0; i<n; i++)
            {
                if (a[i].ff<b[i].ff || (a[i].ff==b[i].ff && a[i].ss>b[i].ss))
                    break;
                else if (a[i].ff==b[i].ff && a[i].ss==b[i].ss)
                    continue;
                else
                {
                    //cerr<<".";
                    ok=0;
                    break;
                }
            }
            if (ok)
            {
                for (int i=n-1; i>=0; i--)
                {
                    if (a[i].ff>b[i].ff || (a[i].ff==b[i].ff && a[i].ss>b[i].ss))
                        break;
                    else if (a[i].ff==b[i].ff && a[i].ss==b[i].ss)
                        continue;
                    else
                    {
                        //cerr<<"*";
                        ok=0;
                        break;
                    }
                }
            }
            if (ok)
                cout<<"TAK\n";
            else
                cout<<"NIE\n";
        }
        else
            cout<<"NIE\n";
        //cerr<<sa<<" "<<sb<<" "<<dplus<<" "<<dminus<<"\n";
        sa=sb=dplus=dminus=0;
    }
    return 0;
}