#include <math.h> #include <algorithm> #include <iostream> #include <vector> using namespace std; /** * Custom method for this task. * Returns a vector of digits of n, from left to right. * If n has any 0, returns an empty vector. */ vector<int> digitsOf(int n) { vector<int> digits; while (n != 0) { int digit = n % 10; if (digit == 0) { return vector<int>{}; } digits.push_back(digit); n = n / 10; } reverse(digits.begin(), digits.end()); return digits; } int sumOfVector(vector<int> nums) { int sum = 0; for (int num : nums) { sum += num; } return sum; } bool isPotychnikovNumber(int num) { vector<int> digits = digitsOf(num); if (digits.empty()) { return false; } for (int digit : digits) { if (num % digit != 0) { return false; } } return true; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int sum = 0; int l, r; cin >> l >> r; for (int num = l; num <= r; num++) { if (isPotychnikovNumber(num)) { sum++; } } cout << sum << endl; return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 | #include <math.h> #include <algorithm> #include <iostream> #include <vector> using namespace std; /** * Custom method for this task. * Returns a vector of digits of n, from left to right. * If n has any 0, returns an empty vector. */ vector<int> digitsOf(int n) { vector<int> digits; while (n != 0) { int digit = n % 10; if (digit == 0) { return vector<int>{}; } digits.push_back(digit); n = n / 10; } reverse(digits.begin(), digits.end()); return digits; } int sumOfVector(vector<int> nums) { int sum = 0; for (int num : nums) { sum += num; } return sum; } bool isPotychnikovNumber(int num) { vector<int> digits = digitsOf(num); if (digits.empty()) { return false; } for (int digit : digits) { if (num % digit != 0) { return false; } } return true; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int sum = 0; int l, r; cin >> l >> r; for (int num = l; num <= r; num++) { if (isPotychnikovNumber(num)) { sum++; } } cout << sum << endl; return 0; } |