#include <bits/stdc++.h>
using namespace std;
typedef vector<int> VI;
typedef long long LL;
#define FOR(x, b, e) for(int x = b; x<= (e); ++x)
#define FORD(x, b, e) for(int x = b; x>= (e); --x)
#define REP(x, n) for(int x = 0; x<(n); ++x)
#define VAR(v, n)typeof(n) v = (n)
#define ALL(c) (c).begin(), (c).end()
#define SIZE(x) ((int)(x).size())
#define FOREACH(i, c) for(VAR(i, (c).begin()); i != (c).end(); ++i)
#define PB pushback
#define ST first
#define ND second
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
int n;
cin >> n;
char a[n], b[n];
int Ap[26], Anp[26], Bp[26], Bnp[26];
FOR(i, 0, 25) {
Ap[i] = 0;
Anp[i] = 0;
Bp[i] = 0;
Bnp[i] = 0;
}
FOR(i, 0, n - 1) {
cin >> a[i];
if (i % 2 == 0) {
Ap[a[i] - 97]++;
}
else {
Anp[a[i] - 97]++;
}
}
FOR(i, 0, n - 1) {
cin >> b[i];
if (i % 2 == 0) {
Bp[b[i] - 97]++;
}
else {
Bnp[b[i] - 97]++;
}
}
bool result = 1;
FOR(i, 0, 25) {
if (Ap[i] != Bp[i] || Anp[i] != Bnp[i]) {
result = 0;
}
}
if (result) {
cout << "TAK\n";
}
else {
cout << "NIE\n";
}
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 | #include <bits/stdc++.h> using namespace std; typedef vector<int> VI; typedef long long LL; #define FOR(x, b, e) for(int x = b; x<= (e); ++x) #define FORD(x, b, e) for(int x = b; x>= (e); --x) #define REP(x, n) for(int x = 0; x<(n); ++x) #define VAR(v, n)typeof(n) v = (n) #define ALL(c) (c).begin(), (c).end() #define SIZE(x) ((int)(x).size()) #define FOREACH(i, c) for(VAR(i, (c).begin()); i != (c).end(); ++i) #define PB pushback #define ST first #define ND second int main() { ios_base::sync_with_stdio(0); cin.tie(0); int n; cin >> n; char a[n], b[n]; int Ap[26], Anp[26], Bp[26], Bnp[26]; FOR(i, 0, 25) { Ap[i] = 0; Anp[i] = 0; Bp[i] = 0; Bnp[i] = 0; } FOR(i, 0, n - 1) { cin >> a[i]; if (i % 2 == 0) { Ap[a[i] - 97]++; } else { Anp[a[i] - 97]++; } } FOR(i, 0, n - 1) { cin >> b[i]; if (i % 2 == 0) { Bp[b[i] - 97]++; } else { Bnp[b[i] - 97]++; } } bool result = 1; FOR(i, 0, 25) { if (Ap[i] != Bp[i] || Anp[i] != Bnp[i]) { result = 0; } } if (result) { cout << "TAK\n"; } else { cout << "NIE\n"; } return 0; } |
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