#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <vector>
using namespace std;
const int N_MAX = 1000000;
vector< pair<int, int> > v[3];
int dane[3][N_MAX];
int puszki[N_MAX][3];
int main() {
int n, m;
scanf("%d %d", &n, &m);
int l_max = -1;
for (int i = 0; i < m; ++i) {
int l, r, k;
scanf("%d %d %d", &l, &r, &k);
dane[k-1][l-1] = max(dane[k-1][l-1], r);
l_max = max(l_max, l-1);
}
for (int i = 0; i < 3; ++i) {
for (int j = 0; j <= l_max; ++j) {
if (dane[i][j] > 0) {
v[i].push_back(make_pair(j, dane[i][j] - 1));
}
}
}
for (int i = 0; i < 3 && v[i].size() > 0; ++i) {
int j = 0;
int act = v[i][0].first; // act = l[0];
int liczba_op = v[i].size();
while (act < n && j < liczba_op) {
while (act <= v[i][j].second) {
puszki[act][i] = 1;
++act;
}
// act = r[j] + 1;
++j;
while (j < liczba_op && v[i][j].second < act) ++j;
// act <= r[j]
if (j >= liczba_op) {
break;
}
act = max(act, v[i][j].first);
// act >= l[j];
}
}
int ile = 0;
for (int i = 0; i < n; ++i) {
if (puszki[i][0] && puszki[i][1] && !puszki[i][2]) ++ile;
}
printf("%d\n", ile);
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 | #include <cstdio> #include <cstdlib> #include <algorithm> #include <vector> using namespace std; const int N_MAX = 1000000; vector< pair<int, int> > v[3]; int dane[3][N_MAX]; int puszki[N_MAX][3]; int main() { int n, m; scanf("%d %d", &n, &m); int l_max = -1; for (int i = 0; i < m; ++i) { int l, r, k; scanf("%d %d %d", &l, &r, &k); dane[k-1][l-1] = max(dane[k-1][l-1], r); l_max = max(l_max, l-1); } for (int i = 0; i < 3; ++i) { for (int j = 0; j <= l_max; ++j) { if (dane[i][j] > 0) { v[i].push_back(make_pair(j, dane[i][j] - 1)); } } } for (int i = 0; i < 3 && v[i].size() > 0; ++i) { int j = 0; int act = v[i][0].first; // act = l[0]; int liczba_op = v[i].size(); while (act < n && j < liczba_op) { while (act <= v[i][j].second) { puszki[act][i] = 1; ++act; } // act = r[j] + 1; ++j; while (j < liczba_op && v[i][j].second < act) ++j; // act <= r[j] if (j >= liczba_op) { break; } act = max(act, v[i][j].first); // act >= l[j]; } } int ile = 0; for (int i = 0; i < n; ++i) { if (puszki[i][0] && puszki[i][1] && !puszki[i][2]) ++ile; } printf("%d\n", ile); return 0; } |
English