#include <bits/stdc++.h> using namespace std; typedef long long LL; typedef long double LD; typedef pair<int, int> PII; typedef pair<LL, LL> PLL; #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() template<typename _T> inline void _DBG(const char *s, _T x) { cerr << s << " = " << x << "\n"; } template<typename _T, typename... args> void _DBG(const char *s, _T x, args... a) { while(*s != ',') cerr << *s++; cerr << " = " << x << ','; _DBG(s + 1, a...); } #ifdef LOCAL #define _upgrade ios_base::sync_with_stdio(0); #define DBG(...) _DBG(#__VA_ARGS__, __VA_ARGS__) #else #define _upgrade ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define DBG(...) (__VA_ARGS__) #define cerr if(0) cout #endif // ********************** CODE ********************** // int cnt[2][26]; int main() { _upgrade int n; cin >> n; for(int i = 0; i < 2; i++) { string s; cin >> s; int val = i == 0 ? 1 : -1; for(int j = 0; j < n; j++) cnt[j % 2][s[j] - 'a'] += val; } bool ok = true; for(int i = 0; i < 2; i++) for(int j = 0; j < 26; j++) ok &= cnt[i][j] == 0; cout << (ok ? "TAK\n" : "NIE\n"); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 | #include <bits/stdc++.h> using namespace std; typedef long long LL; typedef long double LD; typedef pair<int, int> PII; typedef pair<LL, LL> PLL; #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() template<typename _T> inline void _DBG(const char *s, _T x) { cerr << s << " = " << x << "\n"; } template<typename _T, typename... args> void _DBG(const char *s, _T x, args... a) { while(*s != ',') cerr << *s++; cerr << " = " << x << ','; _DBG(s + 1, a...); } #ifdef LOCAL #define _upgrade ios_base::sync_with_stdio(0); #define DBG(...) _DBG(#__VA_ARGS__, __VA_ARGS__) #else #define _upgrade ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define DBG(...) (__VA_ARGS__) #define cerr if(0) cout #endif // ********************** CODE ********************** // int cnt[2][26]; int main() { _upgrade int n; cin >> n; for(int i = 0; i < 2; i++) { string s; cin >> s; int val = i == 0 ? 1 : -1; for(int j = 0; j < n; j++) cnt[j % 2][s[j] - 'a'] += val; } bool ok = true; for(int i = 0; i < 2; i++) for(int j = 0; j < 26; j++) ok &= cnt[i][j] == 0; cout << (ok ? "TAK\n" : "NIE\n"); return 0; } |