#pragma GCC optimize ("O3") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> ii; typedef vector<int> vi; const int INF = 0x3f3f3f3f; #define FOR(i,b,e) for(int i = (b); i < (e); i++) #define TRAV(x,a) for(auto &x: (a)) #define SZ(x) ((int)x.size()) #define PB push_back #define X first #define Y second const int N = 2e6+10; int cnt[N][2]; void solve(){ int n, a, b, c, ans = 0; cin >> n; FOR(i, 0, n){ cin >> a >> b >> c; cnt[b-c+N/2][a-1]++; } FOR(i, 0, N) ans += min(cnt[i][0], cnt[i][1]); cout << ans << '\n'; } int main(){ ios::sync_with_stdio(0); cin.tie(0); // int tt; cin >> tt; // FOR(te, 0, tt) solve(); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 | #pragma GCC optimize ("O3") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> ii; typedef vector<int> vi; const int INF = 0x3f3f3f3f; #define FOR(i,b,e) for(int i = (b); i < (e); i++) #define TRAV(x,a) for(auto &x: (a)) #define SZ(x) ((int)x.size()) #define PB push_back #define X first #define Y second const int N = 2e6+10; int cnt[N][2]; void solve(){ int n, a, b, c, ans = 0; cin >> n; FOR(i, 0, n){ cin >> a >> b >> c; cnt[b-c+N/2][a-1]++; } FOR(i, 0, N) ans += min(cnt[i][0], cnt[i][1]); cout << ans << '\n'; } int main(){ ios::sync_with_stdio(0); cin.tie(0); // int tt; cin >> tt; // FOR(te, 0, tt) solve(); return 0; } |