#include <cstdio> #include <queue> using namespace std; #define MAX_N 2010 #define MAX_M 2010 int N, M, K; int f[MAX_N][MAX_M]; queue<pair<int, int>> q; void g() { while (!q.empty()) { pair<int, int> c = q.front(); q.pop(); int i = c.first; int j = c.second; if (i == N - 1 && j == M - 1) { return; } if (i > 0 && f[i - 1][j] == 0) { f[i - 1][j] = f[i][j] + 1; q.push(make_pair(i - 1, j)); } if (j > 0 && f[i][j - 1] == 0) { f[i][j - 1] = f[i][j] + 1; q.push(make_pair(i, j - 1)); } if (i < N - 1 && f[i + 1][j] == 0) { f[i + 1][j] = f[i][j] + 1; q.push(make_pair(i + 1, j)); } if (j < M - 1 && f[i][j + 1] == 0) { f[i][j + 1] = f[i][j] + 1; q.push(make_pair(i, j + 1)); } } } int main() { char r[MAX_M]; int a, b; scanf("%d %d %d", &N, &M, &K); for (int i = 0; i < N; ++i) { scanf("%s", r); for (int j = 0; j < M; ++j) { if (r[j] == 'X') { f[i][j] = -1; } } } f[0][0] = 1; q.push(make_pair(0, 0)); g(); long long u = N + M - 2 + (f[N - 1][M - 1] - N - M + 1) / 2; long long d = u - N - M + 2; long long m = 0; int c = 0; for (int i = 0; i < K; ++i) { scanf("%d %d", &a, &b); long long t = u * a + d * b; if (m == 0 || t < m) { m = t; c = 1; } else if (t == m) { c++; } } printf("%lld %d\n", m, c); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 | #include <cstdio> #include <queue> using namespace std; #define MAX_N 2010 #define MAX_M 2010 int N, M, K; int f[MAX_N][MAX_M]; queue<pair<int, int>> q; void g() { while (!q.empty()) { pair<int, int> c = q.front(); q.pop(); int i = c.first; int j = c.second; if (i == N - 1 && j == M - 1) { return; } if (i > 0 && f[i - 1][j] == 0) { f[i - 1][j] = f[i][j] + 1; q.push(make_pair(i - 1, j)); } if (j > 0 && f[i][j - 1] == 0) { f[i][j - 1] = f[i][j] + 1; q.push(make_pair(i, j - 1)); } if (i < N - 1 && f[i + 1][j] == 0) { f[i + 1][j] = f[i][j] + 1; q.push(make_pair(i + 1, j)); } if (j < M - 1 && f[i][j + 1] == 0) { f[i][j + 1] = f[i][j] + 1; q.push(make_pair(i, j + 1)); } } } int main() { char r[MAX_M]; int a, b; scanf("%d %d %d", &N, &M, &K); for (int i = 0; i < N; ++i) { scanf("%s", r); for (int j = 0; j < M; ++j) { if (r[j] == 'X') { f[i][j] = -1; } } } f[0][0] = 1; q.push(make_pair(0, 0)); g(); long long u = N + M - 2 + (f[N - 1][M - 1] - N - M + 1) / 2; long long d = u - N - M + 2; long long m = 0; int c = 0; for (int i = 0; i < K; ++i) { scanf("%d %d", &a, &b); long long t = u * a + d * b; if (m == 0 || t < m) { m = t; c = 1; } else if (t == m) { c++; } } printf("%lld %d\n", m, c); return 0; } |