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#include <vector>
#include <iostream>
#include <sstream>
#include <math.h>
#include <sys/time.h>
#include <cstdlib>
#include <algorithm>
#include <cassert>
#include <cstring>
#include <fstream>
#include <set>
#include <map>
#include <iomanip>
#include <queue>
#include <limits>

#define FOR(i,a,b)  for(__typeof(b) i=(a);i<(b);++i)
#define REP(i,a)    FOR(i,0,a)
#define FOREACH(x,c)   for(__typeof(c.begin()) x=c.begin();x != c.end(); x++)
#define ALL(c)      c.begin(),c.end()
#define CLEAR(c)    memset(c,0,sizeof(c))
#define SIZE(c) (int) ((c).size())

#define PB          push_back
#define MP          make_pair
#define X           first
#define Y           second

#define ULL         unsigned long long
#define LL          long long
#define LD          long double
#define II         pair<int, int>
#define DD         pair<double, double>
#define FF          pair<float,float>

#define VC	    vector
#define VI          VC<int>
#define VVI         VC<VI>
#define VVVI        VC<VVI>
#define VD          VC<double>
#define VS          VC<string>
#define VII         VC<II>
#define VDD         VC<DD>
#define VFF         VC<FF>
#define VVD         VC<VD>
#define VVVD        VC<VVD>
#define VULL         VC<ULL>

#define DB(a)       cerr << #a << ": " << a << endl;

using namespace std;

template<class T> void print(VC < T > v) {cerr << "[";if (SIZE(v) != 0) cerr << v[0]; FOR(i, 1, SIZE(v)) cerr << "," << v[i]; cerr << "]\n";}
template<class T> string i2s(T &x) { ostringstream o; o << x; return o.str(); }
VS split(string &s, char c = ' ') {VS all; int p = 0, np; while (np = s.find(c, p), np >= 0) {all.PB(s.substr(p, np - p)); p = np + 1;} if (p < SIZE(s)) all.PB(s.substr(p)); return all;}

#define INFTY 1e9

int dx[4] = {1,-1, 0, 0};
int dy[4] = {0, 0, 1,-1};

int main(int argc, char *argv[]){
    int n,m,k;
    cin >> n >> m >> k;
    VS board(n);
    REP(i,n) cin >> board[i];
    VVI sol(n,VI(m,INFTY));
    sol[0][0] = 0;

    queue<II> q;
    q.push(MP(0,0));
    while(!q.empty()){
        II e = q.front();
        q.pop();
        int x = e.X, y = e.Y;
        if (x == n-1 && y == m-1)
            break;
        REP(d,4){
            int xx = x+dx[d];
            int yy = y+dy[d];
            if (xx < 0 || xx >= n)
                continue;
            if (yy < 0 || yy >= m)
                continue;
            if (board[xx][yy] == 'X')
                continue;
            if (sol[xx][yy] != INFTY)
                continue;
            sol[xx][yy] = sol[x][y]+1;
            q.push(MP(xx,yy));
        }
    }
    int a = n-1 + m-1;
    int b = (sol[n-1][m-1] - a)/2;
    a += b;

    long long best = numeric_limits<long long>::max();
    int cnt = 1;
    REP(i,k){
        long long x,y;
        cin >> x >> y;
        long long v = x*a + y*b;
        if (v < best){
            best = v;
            cnt = 1;
        } else if (v == best)
            cnt++;
    }

    cout << best << " " << cnt << endl;

    return 0;
}