#include <bits/stdc++.h> using namespace std; typedef long long LL; typedef long double LD; typedef pair<int, int> PII; typedef pair<LL, LL> PLL; #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() template<typename _T> inline void _DBG(const char *s, _T x) { cerr << s << " = " << x << "\n"; } template<typename _T, typename... args> void _DBG(const char *s, _T x, args... a) { while(*s != ',') cerr << *s++; cerr << " = " << x << ','; _DBG(s + 1, a...); } #ifdef LOCAL #define _upgrade ios_base::sync_with_stdio(0); #define DBG(...) _DBG(#__VA_ARGS__, __VA_ARGS__) #else #define _upgrade ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define DBG(...) (__VA_ARGS__) #define cerr if(0) cout #endif // ********************** CODE ********************** // const int N = 2005; int n, k, T[N]; int main() { _upgrade cin >> n >> k; for (int i = 1; i <= n; i++) cin >> T[i]; sort(T + 1, T + n + 1, [](const int &a, const int &b) { return a > b; }); int ans = k; while (ans + 1 <= n && T[ans + 1] == T[ans]) ans++; cout << ans << "\n"; return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 | #include <bits/stdc++.h> using namespace std; typedef long long LL; typedef long double LD; typedef pair<int, int> PII; typedef pair<LL, LL> PLL; #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() template<typename _T> inline void _DBG(const char *s, _T x) { cerr << s << " = " << x << "\n"; } template<typename _T, typename... args> void _DBG(const char *s, _T x, args... a) { while(*s != ',') cerr << *s++; cerr << " = " << x << ','; _DBG(s + 1, a...); } #ifdef LOCAL #define _upgrade ios_base::sync_with_stdio(0); #define DBG(...) _DBG(#__VA_ARGS__, __VA_ARGS__) #else #define _upgrade ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define DBG(...) (__VA_ARGS__) #define cerr if(0) cout #endif // ********************** CODE ********************** // const int N = 2005; int n, k, T[N]; int main() { _upgrade cin >> n >> k; for (int i = 1; i <= n; i++) cin >> T[i]; sort(T + 1, T + n + 1, [](const int &a, const int &b) { return a > b; }); int ans = k; while (ans + 1 <= n && T[ans + 1] == T[ans]) ans++; cout << ans << "\n"; return 0; } |