#pragma GCC optimize ("O3")
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<int> vi;
typedef double K;
constexpr int INF = 0x3f3f3f3f;
#define FOR(i, b, e) for(int i = (b); i < (e); i++)
#define TRAV(x, a) for(auto &x: (a))
#define SZ(x) ((int)(x).size())
#define PB push_back
#define X first
#define Y second
constexpr int mod = 1e9 + 7;
constexpr int N = 3010;
int kon[N], zdr[N], nos[N], zak[N];
void solve() {
int n, m;
cin >> n >> m;
kon[2] = 1;
FOR(i, 1, n + 1) {
for(int j = n; j >= 0; j--) {
nos[j + 2] = 1ll * zak[j + 2] * (m - j - 1) % mod;
zak[j + 2] = (1ll * zdr[j + 2] + nos[j + 1] + zak[j + 2]) * j % mod;
zdr[j + 2] = (1ll * kon[j + 2] + zdr[j + 2] + nos[j + 1]) * (m - j) % mod;
kon[j + 2] = (1ll * zdr[j + 1] + nos[j] + zak[j + 1]) % mod;
}
}
int sum = 0;
FOR(i, 0, n + 3) sum = (sum + kon[i]) % mod;
cout << sum << '\n';
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
// int tt; cin >> tt;
// FOR(te, 0, tt) {
// // cout << "Case #" << te + 1 << ": ";
// solve();
// }
solve();
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 | #pragma GCC optimize ("O3") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> ii; typedef vector<int> vi; typedef double K; constexpr int INF = 0x3f3f3f3f; #define FOR(i, b, e) for(int i = (b); i < (e); i++) #define TRAV(x, a) for(auto &x: (a)) #define SZ(x) ((int)(x).size()) #define PB push_back #define X first #define Y second constexpr int mod = 1e9 + 7; constexpr int N = 3010; int kon[N], zdr[N], nos[N], zak[N]; void solve() { int n, m; cin >> n >> m; kon[2] = 1; FOR(i, 1, n + 1) { for(int j = n; j >= 0; j--) { nos[j + 2] = 1ll * zak[j + 2] * (m - j - 1) % mod; zak[j + 2] = (1ll * zdr[j + 2] + nos[j + 1] + zak[j + 2]) * j % mod; zdr[j + 2] = (1ll * kon[j + 2] + zdr[j + 2] + nos[j + 1]) * (m - j) % mod; kon[j + 2] = (1ll * zdr[j + 1] + nos[j] + zak[j + 1]) % mod; } } int sum = 0; FOR(i, 0, n + 3) sum = (sum + kon[i]) % mod; cout << sum << '\n'; } int main() { ios::sync_with_stdio(0); cin.tie(0); // int tt; cin >> tt; // FOR(te, 0, tt) { // // cout << "Case #" << te + 1 << ": "; // solve(); // } solve(); return 0; } |
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