#include <bits/stdc++.h> using namespace std; #define REP(i, n) for (int i = 0; i < (n); ++i) #define SZ(a) ((int)(a).size()) #define ALL(a) (a).begin(), (a).end() using ll = long long; using vi = vector<int>; using vvi = vector<vi>; constexpr int kInf = 1000 * 1000 * 1000 + 7; constexpr long long kInfLL = 1e18; // #include <atcoder/fenwicktree> // using namespace atcoder; // using mint = modint998244353; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t; cin >> t; REP(i, t) { int n; cin >> n; string s; cin >> s; vi a, b; REP(i, n) { if (s[i] == '1') continue; int j = i; while (j < n && s[i] == s[j]) ++j; int len = j - i; if (i == 0 || j == n) { a.push_back(len); } else { b.push_back(len); } i = j - 1; } sort(a.rbegin(), a.rend()); sort(b.rbegin(), b.rend()); int mx = 0; for (int mask = 0; mask < (1 << SZ(a)); ++mask) { REP(i, SZ(b) + 1) { vi cur; bool failed = false; int result = 0; int c = 0; REP(j, 2) if (mask & (1 << j)) { result += max(a[j] - 2 * i - j, 0); ++c; } REP(j, i) { if (b[j] <= 2 * j) { failed = true; break; } result += max(b[j] - 2 * j - i, 1); } if (i < SZ(b) && b[i] - 2 * (2 * i + c) > 0) { ++result; } mx = max(mx, result); if (failed) break; } } cout << n - mx << '\n'; } }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 | #include <bits/stdc++.h> using namespace std; #define REP(i, n) for (int i = 0; i < (n); ++i) #define SZ(a) ((int)(a).size()) #define ALL(a) (a).begin(), (a).end() using ll = long long; using vi = vector<int>; using vvi = vector<vi>; constexpr int kInf = 1000 * 1000 * 1000 + 7; constexpr long long kInfLL = 1e18; // #include <atcoder/fenwicktree> // using namespace atcoder; // using mint = modint998244353; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t; cin >> t; REP(i, t) { int n; cin >> n; string s; cin >> s; vi a, b; REP(i, n) { if (s[i] == '1') continue; int j = i; while (j < n && s[i] == s[j]) ++j; int len = j - i; if (i == 0 || j == n) { a.push_back(len); } else { b.push_back(len); } i = j - 1; } sort(a.rbegin(), a.rend()); sort(b.rbegin(), b.rend()); int mx = 0; for (int mask = 0; mask < (1 << SZ(a)); ++mask) { REP(i, SZ(b) + 1) { vi cur; bool failed = false; int result = 0; int c = 0; REP(j, 2) if (mask & (1 << j)) { result += max(a[j] - 2 * i - j, 0); ++c; } REP(j, i) { if (b[j] <= 2 * j) { failed = true; break; } result += max(b[j] - 2 * j - i, 1); } if (i < SZ(b) && b[i] - 2 * (2 * i + c) > 0) { ++result; } mx = max(mx, result); if (failed) break; } } cout << n - mx << '\n'; } } |