#include <bits/stdc++.h>
using namespace std;
#define REP(i, n) for (int i = 0; i < (n); ++i)
#define SZ(a) ((int)(a).size())
#define ALL(a) (a).begin(), (a).end()
using ll = long long;
using vi = vector<int>;
using vvi = vector<vi>;
constexpr int kInf = 1000 * 1000 * 1000 + 7;
constexpr long long kInfLL = 1e18;
// #include <atcoder/fenwicktree>
// using namespace atcoder;
// using mint = modint998244353;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int t;
cin >> t;
REP(i, t) {
int n;
cin >> n;
string s;
cin >> s;
vi a, b;
REP(i, n) {
if (s[i] == '1') continue;
int j = i;
while (j < n && s[i] == s[j]) ++j;
int len = j - i;
if (i == 0 || j == n) {
a.push_back(len);
} else {
b.push_back(len);
}
i = j - 1;
}
sort(a.rbegin(), a.rend());
sort(b.rbegin(), b.rend());
int mx = 0;
for (int mask = 0; mask < (1 << SZ(a)); ++mask) {
REP(i, SZ(b) + 1) {
vi cur;
bool failed = false;
int result = 0;
int c = 0;
REP(j, 2) if (mask & (1 << j)) {
result += max(a[j] - 2 * i - j, 0);
++c;
}
REP(j, i) {
if (b[j] <= 2 * j) {
failed = true;
break;
}
result += max(b[j] - 2 * j - i, 1);
}
if (i < SZ(b) && b[i] - 2 * (2 * i + c) > 0) {
++result;
}
mx = max(mx, result);
if (failed) break;
}
}
cout << n - mx << '\n';
}
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 | #include <bits/stdc++.h> using namespace std; #define REP(i, n) for (int i = 0; i < (n); ++i) #define SZ(a) ((int)(a).size()) #define ALL(a) (a).begin(), (a).end() using ll = long long; using vi = vector<int>; using vvi = vector<vi>; constexpr int kInf = 1000 * 1000 * 1000 + 7; constexpr long long kInfLL = 1e18; // #include <atcoder/fenwicktree> // using namespace atcoder; // using mint = modint998244353; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t; cin >> t; REP(i, t) { int n; cin >> n; string s; cin >> s; vi a, b; REP(i, n) { if (s[i] == '1') continue; int j = i; while (j < n && s[i] == s[j]) ++j; int len = j - i; if (i == 0 || j == n) { a.push_back(len); } else { b.push_back(len); } i = j - 1; } sort(a.rbegin(), a.rend()); sort(b.rbegin(), b.rend()); int mx = 0; for (int mask = 0; mask < (1 << SZ(a)); ++mask) { REP(i, SZ(b) + 1) { vi cur; bool failed = false; int result = 0; int c = 0; REP(j, 2) if (mask & (1 << j)) { result += max(a[j] - 2 * i - j, 0); ++c; } REP(j, i) { if (b[j] <= 2 * j) { failed = true; break; } result += max(b[j] - 2 * j - i, 1); } if (i < SZ(b) && b[i] - 2 * (2 * i + c) > 0) { ++result; } mx = max(mx, result); if (failed) break; } } cout << n - mx << '\n'; } } |
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