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// Arti1990, II UWr

#include <bits/stdc++.h>

#define forr(i, n)                  for(int i=0; i<n; i++)
#define FOREACH(iter, coll)         for(auto iter = coll.begin(); iter != coll.end(); ++iter)
#define FOREACHR(iter, coll)        for(auto iter = coll.rbegin(); iter != coll.rend(); ++iter)
#define lbound(P,K,FUN)             ({auto SSS=P, PPP = P-1, KKK=(K)+1; while(PPP+1!=KKK) {SSS = (PPP+(KKK-PPP)/2); if(FUN(SSS)) KKK = SSS; else PPP = SSS;} PPP;})
#define testy()                     int _tests; scanf("%d", &_tests); FOR(_test, 1, _tests)
#define CLEAR(tab)                  memset(tab, 0, sizeof(tab))
#define CONTAIN(el, coll)           (coll.find(el) != coll.end())
#define FOR(i, a, b)                for(int i=a; i<=b; i++)
#define FORD(i, a, b)               for(int i=a; i>=b; i--)
#define MP                          make_pair
#define PB                          push_back
#define ff                          first
#define ss                          second
#define deb(X)                      X;

#define M 1000000007
#define INF 1000000000000000007LL

using namespace std;

int n, k;
long long a[100007], b[100007];
char slowo[100007];

struct word
{
    char c;
    word *next;

    word()
    {
        c = '.';
        next = nullptr;
    }

    word(char cc, word* nxt)
    {
        c = cc;
        next = nxt;
    }
};

struct elem
{
    long long suf;
    long long res;
    word *next;

    elem(){
        suf = 0;
        res = 0;
        next = nullptr;
    }

    elem(long long s, long long r, word *w){
        suf = s;
        res = r;
        next = w;
    }
};
vector <elem> tab[2][100007];

void wypisz(vector <elem> v)
{
    forr(i, v.size())
        cout << "   " << i << ": suf = " << v[i].suf << ", res = " << v[i].res << ", letter: " << v[i].next->c << endl;
}

bool sprawdz(vector <elem> v, string str)
{
    return 0;
    for(int i=1; i<v.size(); i++)
        if(v[i-1].suf >= v[i].suf || v[i-1].res <= v[i].res)
        {
            cout << "NIE DZIALA! " << str << endl;
            return 1;
        }
    return 0;
}

vector <elem> rozszerz(vector <elem> &v, long long val, char c)
{
    vector <elem> res;
    elem e;
    sprawdz(v, "przed rozszerz");
    for(auto el : v)
    {
        e.suf = max(el.suf + val, 0ll);
        e.res = max(el.res, e.suf);
        e.next = new word(c, el.next);

        while(!res.empty() && res.back().suf == e.suf && res.back().res >= e.res)
            res.pop_back();
        if(res.empty() || (res.back().suf < e.suf && res.back().res > e.res))
            res.PB(e);
    }
    if(sprawdz(res, "rozszerz"))
    {
        wypisz(v);
        cout << "val: " << val << ", c: " << c << endl;
        wypisz(res);
    }
    return res;
}

// sortujemy po suf, suf musza byc rosnace, res malejace
void polacz(vector <elem> va, vector <elem> vb, vector <elem> &v)
{
    int ia=0, ib = 0;
    elem e;
    while(ia < va.size() || ib < vb.size())
    {
        if(ia < va.size() && (ib == vb.size() || va[ia].suf < vb[ib].suf || (va[ia].suf == vb[ib].suf && va[ia].res < vb[ib].res)))
            e = va[ia++];
        else
            e = vb[ib++];
        if(v.empty() || (e.suf > v.back().suf && e.res < v.back().res))
            v.PB(e);
    }
    sprawdz(v, "polacz");
}

int solve()
{
    scanf("%d %d", &n, &k);
    FOR(i, 1, n)
        scanf("%lld", &a[i]);
    FOR(i, 1, n)
        scanf("%lld", &b[i]);


    tab[0][0].PB(elem(0, 0, nullptr));
    int bb = 0;
    FOR(i, 1, n)
    {
        bb = 1-bb;
        FOR(j, 0, k)
            tab[bb][j].clear();

        int pocz = max(0, k-(n-i));
        int kon = min(i, k);
        FOR(j, pocz, kon)
        {
            if(j == 0)
                tab[bb][j] = rozszerz(tab[1-bb][j], b[i], 'B');
            else
                polacz(rozszerz(tab[1-bb][j-1], a[i], 'A'), rozszerz(tab[1-bb][j], b[i], 'B'), tab[bb][j]);
//            cout << "wektor[" << i << "][" << j << "]:" << endl;
//            wypisz(tab[bb][j]);
        }
    }

    int j = k;
    word *p = tab[bb][k].back().next;
    FORD(i, n-1, 0)
    {
        slowo[i] = p->c;
        p = p->next;
    }

//    printf("%lld\n", tab[bb][k].back().res);
    printf("%lld\n%s\n", tab[bb][k].back().res, slowo);


    return 0;
}

int main()
{
    solve();

    return 0;
}