1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
// Grzegorz Ryn
// Jagiellonian University

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

#define pb push_back
#define eb emplace_back
#define mp make_pair
#define mt make_tuple
#define st first
#define nd second
#define all(__VAR) (__VAR).begin(), (__VAR).end()
#define DEBUG(__VAR) cout << #__VAR << ": " << __VAR << endl;

template <typename T, typename U>
ostream & operator<<(ostream &out, const pair<T, U> &var) {
	cout << "{" << var.st << ", " << var.nd << "}";
	return out;
}

template <typename T>
ostream & operator<<(ostream &out, const vector<T> &var) {
	cout << "[";
	for(int i=0; i<(int)var.size()-1; i++) {
		cout << var[i] << ", ";
	}
	if(var.size()>0)
		cout << var.back();
	cout << "]" << endl;
	
	return out;
}

const int inf = 1'000'000'000;

int main() {
	ios_base::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	
	string a, b;
	cin >> a >> b;

	int MAXN = 5000 + 10;
	vector<int> res(MAXN, 0);

	int N = a.length(), M = b.length();

	for(int i=0; i<N; i++) {
		res[i] += (int)(a[N-i-1]-'0');
	}
	for(int i=0; i<M; i++) {
		res[i] += (int)(b[M-i-1]-'0');
	}
	for(int i=0; i<MAXN-1; i++) {
		res[i+1] += res[i]/10;
		res[i] %= 10;
	}

	while(res.back() == 0) {
		res.pop_back();
	}

	while(res.size() > 0) {
		cout << res.back();
		res.pop_back();
	}
	cout << '\n';

	return 0;
}