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// Arti1990, II UWr

#include <bits/stdc++.h>

#define forr(i, n)                  for(int i=0; i<n; i++)
#define FOREACH(iter, coll)         for(auto iter = coll.begin(); iter != coll.end(); ++iter)
#define FOREACHR(iter, coll)        for(auto iter = coll.rbegin(); iter != coll.rend(); ++iter)
#define lbound(P,K,FUN)             ({auto SSS=P, PPP = P-1, KKK=(K)+1; while(PPP+1!=KKK) {SSS = (PPP+(KKK-PPP)/2); if(FUN(SSS)) KKK = SSS; else PPP = SSS;} PPP;})
#define testy()                     int _tests; scanf("%d", &_tests); FOR(_test, 1, _tests)
#define CLEAR(tab)                  memset(tab, 0, sizeof(tab))
#define CONTAIN(el, coll)           (coll.find(el) != coll.end())
#define FOR(i, a, b)                for(int i=a; i<=b; i++)
#define FORD(i, a, b)               for(int i=a; i>=b; i--)
#define MP                          make_pair
#define PB                          push_back
#define ff                          first
#define ss                          second
#define deb(X)                      X;

#define M 1000000007
#define INF 1000000007LL

using namespace std;

int n, m, a, d1, d2;
char slowo[1000007];
int t1[1000007], t2[1000007];

int solve()
{
    scanf("%s", slowo);
    d1 = strlen(slowo);
    forr(i, d1)
        t1[i] = slowo[d1-1-i]-'0';
    scanf("%s", slowo);
    d2 = strlen(slowo);
    forr(i, d2)
        t2[i] = slowo[d2-1-i]-'0';
    d1 = max(d1, d2);
    forr(i, d1)
    {
        t1[i] += t2[i];
        if(t1[i] > 9)
        {
            t1[i+1] += t1[i]/10;
            t1[i] %= 10;
        }
    }
    while(t1[d1] != 0)
    {
        t1[d1+1] += t1[d1]/10;
        t1[d1] %= 10;
        d1++;
    }
    FORD(i, d1-1, 0)
        printf("%d", t1[i]);
    printf("\n");

    return 0;
}

int main()
{
    solve();

    return 0;
}