#include <bits/stdc++.h>
using namespace std;
#define rep(i,a,n) for (int i=a;i<n;i++)
#define per(i,a,n) for (int i=n-1;i>=a;i--)
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
#define SZ(x) ((int)(x).size())
typedef vector<int> VI;
typedef basic_string<int> BI;
typedef long long ll;
typedef pair<int,int> PII;
typedef double db;
mt19937 mrand(1);
const ll mod=1000000007;
int rnd(int x) { return mrand() % x;}
ll powmod(ll a,ll b) {ll res=1;a%=mod; assert(b>=0); for(;b;b>>=1){if(b&1)res=res*a%mod;a=a*a%mod;}return res;}
ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;}
// head
const int N=50100;
int n,b[N][3],dp[N][3],a[N];
int solve() {
rep(i,0,n) {
b[i][0]=a[i],b[i][1]=1e9,b[i][2]=-1e9;
dp[i][0]=dp[i][1]=dp[i][2]=1e9;
}
dp[0][0]=0;
dp[0][1]=1;
dp[0][2]=1;
rep(i,1,n) rep(j,0,3) rep(k,0,3) {
if ((i%2==1&&b[i-1][j]<b[i][k])||
(i%2==0&&b[i-1][j]>b[i][k]))
dp[i][k]=min(dp[i][k],dp[i-1][j]+(k!=0));
}
return min({dp[n-1][0],dp[n-1][1],dp[n-1][2]});
}
int main() {
scanf("%d",&n);
rep(i,0,n) scanf("%d",&a[i]);
int ans=solve();
rep(i,0,n) a[i]=-a[i];
ans=min(ans,solve());
printf("%d\n",ans);
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 | #include <bits/stdc++.h> using namespace std; #define rep(i,a,n) for (int i=a;i<n;i++) #define per(i,a,n) for (int i=n-1;i>=a;i--) #define pb push_back #define eb emplace_back #define mp make_pair #define all(x) (x).begin(),(x).end() #define fi first #define se second #define SZ(x) ((int)(x).size()) typedef vector<int> VI; typedef basic_string<int> BI; typedef long long ll; typedef pair<int,int> PII; typedef double db; mt19937 mrand(1); const ll mod=1000000007; int rnd(int x) { return mrand() % x;} ll powmod(ll a,ll b) {ll res=1;a%=mod; assert(b>=0); for(;b;b>>=1){if(b&1)res=res*a%mod;a=a*a%mod;}return res;} ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;} // head const int N=50100; int n,b[N][3],dp[N][3],a[N]; int solve() { rep(i,0,n) { b[i][0]=a[i],b[i][1]=1e9,b[i][2]=-1e9; dp[i][0]=dp[i][1]=dp[i][2]=1e9; } dp[0][0]=0; dp[0][1]=1; dp[0][2]=1; rep(i,1,n) rep(j,0,3) rep(k,0,3) { if ((i%2==1&&b[i-1][j]<b[i][k])|| (i%2==0&&b[i-1][j]>b[i][k])) dp[i][k]=min(dp[i][k],dp[i-1][j]+(k!=0)); } return min({dp[n-1][0],dp[n-1][1],dp[n-1][2]}); } int main() { scanf("%d",&n); rep(i,0,n) scanf("%d",&a[i]); int ans=solve(); rep(i,0,n) a[i]=-a[i]; ans=min(ans,solve()); printf("%d\n",ans); } |
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