// Arti1990, II UWr
#include <bits/stdc++.h>
#define forr(i, n) for(int i=0; i<n; i++)
#define FOREACH(iter, coll) for(auto iter = coll.begin(); iter != coll.end(); ++iter)
#define FOREACHR(iter, coll) for(auto iter = coll.rbegin(); iter != coll.rend(); ++iter)
#define lbound(P,K,FUN) ({auto SSS=P, PPP = P-1, KKK=(K)+1; while(PPP+1!=KKK) {SSS = (PPP+(KKK-PPP)/2); if(FUN(SSS)) KKK = SSS; else PPP = SSS;} PPP;})
#define testy() int _tests; scanf("%d", &_tests); FOR(_test, 1, _tests)
#define CLEAR(tab) memset(tab, 0, sizeof(tab))
#define CONTAIN(el, coll) (coll.find(el) != coll.end())
#define FOR(i, a, b) for(int i=a; i<=b; i++)
#define FORD(i, a, b) for(int i=a; i>=b; i--)
#define MP make_pair
#define PB push_back
#define ff first
#define ss second
#define deb(X) X;
#define M 1000000007
#define INF 1000000007LL
using namespace std;
int n, m, tab[200007], a;
long long dp[200007][3];
int ile[3][2], numer[128], suma;
string slowo;
char c;
void init()
{
numer['Z'] = 1;
numer['C'] = 2;
dp[0][0] = 1;
FOR(i, 1, 200003)
forr(j, 3)
{
dp[i][j] = (dp[i-1][(j+1)%3] + dp[i-1][(j+2)%3]) % M;
//cout << dp[i][j] << " ";
}
}
long long policz()
{
/* forr(i, 3)
{
cout << "ile " << i << ":";
forr(j, 2)
cout << " " << ile[i][j];
cout << '\n';
}
*/
long long res = 0;
forr(i, 3)
if((i+suma)%3 != 0)
res += dp[ile[0][0] + ile[0][1]][i];
if(n > 1 && ile[1][0] == 0 && ile[2][1] == 0 && n%2 == 1)
res--;
if(n > 1 && ile[1][1] == 0 && ile[2][0] == 0 && n%2 == 1)
res--;
return (res + M)%M;
}
int solve()
{
cin >> n >> m;
cin >> slowo;
FOR(i, 1, n)
{
tab[i] = numer[slowo[i-1]];
ile[tab[i]][i%2]++;
suma += tab[i];
}
cout << policz() << '\n';
forr(i, m)
{
cin >> a >> c;
ile[tab[a]][a%2]--;
suma -= tab[a];
tab[a] = numer[c];
ile[tab[a]][a%2]++;
suma += tab[a];
cout << policz() << '\n';
}
return 0;
}
int main()
{
std::ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
init();
solve();
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 | // Arti1990, II UWr #include <bits/stdc++.h> #define forr(i, n) for(int i=0; i<n; i++) #define FOREACH(iter, coll) for(auto iter = coll.begin(); iter != coll.end(); ++iter) #define FOREACHR(iter, coll) for(auto iter = coll.rbegin(); iter != coll.rend(); ++iter) #define lbound(P,K,FUN) ({auto SSS=P, PPP = P-1, KKK=(K)+1; while(PPP+1!=KKK) {SSS = (PPP+(KKK-PPP)/2); if(FUN(SSS)) KKK = SSS; else PPP = SSS;} PPP;}) #define testy() int _tests; scanf("%d", &_tests); FOR(_test, 1, _tests) #define CLEAR(tab) memset(tab, 0, sizeof(tab)) #define CONTAIN(el, coll) (coll.find(el) != coll.end()) #define FOR(i, a, b) for(int i=a; i<=b; i++) #define FORD(i, a, b) for(int i=a; i>=b; i--) #define MP make_pair #define PB push_back #define ff first #define ss second #define deb(X) X; #define M 1000000007 #define INF 1000000007LL using namespace std; int n, m, tab[200007], a; long long dp[200007][3]; int ile[3][2], numer[128], suma; string slowo; char c; void init() { numer['Z'] = 1; numer['C'] = 2; dp[0][0] = 1; FOR(i, 1, 200003) forr(j, 3) { dp[i][j] = (dp[i-1][(j+1)%3] + dp[i-1][(j+2)%3]) % M; //cout << dp[i][j] << " "; } } long long policz() { /* forr(i, 3) { cout << "ile " << i << ":"; forr(j, 2) cout << " " << ile[i][j]; cout << '\n'; } */ long long res = 0; forr(i, 3) if((i+suma)%3 != 0) res += dp[ile[0][0] + ile[0][1]][i]; if(n > 1 && ile[1][0] == 0 && ile[2][1] == 0 && n%2 == 1) res--; if(n > 1 && ile[1][1] == 0 && ile[2][0] == 0 && n%2 == 1) res--; return (res + M)%M; } int solve() { cin >> n >> m; cin >> slowo; FOR(i, 1, n) { tab[i] = numer[slowo[i-1]]; ile[tab[i]][i%2]++; suma += tab[i]; } cout << policz() << '\n'; forr(i, m) { cin >> a >> c; ile[tab[a]][a%2]--; suma -= tab[a]; tab[a] = numer[c]; ile[tab[a]][a%2]++; suma += tab[a]; cout << policz() << '\n'; } return 0; } int main() { std::ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); init(); solve(); return 0; } |
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