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//#pragma GCC optimize("Ofast")
//#pragma GCC optimize ("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")

#pragma warning(disable:4786)
#pragma warning(disable:4996)
#include <random>
#include <chrono>
#include <ctime>
#include<list>
#include <numeric>
#include<bitset>
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<vector>
#include<set>
#include<map>
#include<functional>
#include<string>
#include<cstring>
#include<cstdlib>
#include<queue>
#include<utility>
#include<fstream>
#include<sstream>
#include<cmath>
#include<stack>
#include<assert.h>
#include<unordered_map>
#include<unordered_set>
#include <array>
#include <complex>
#include<iomanip>
using namespace std;

#define MEM(a, b) memset(a, (b), sizeof(a))
#define CLR(a) memset(a, 0, sizeof(a))
#define MAX(a, b) ((a) > (b) ? (a) : (b))
#define MIN(a, b) ((a) < (b) ? (a) : (b))
#define ABS(X) ( (X) > 0 ? (X) : ( -(X) ) )
#define S(X) ( (X) * (X) )
#define SZ(V) (int )V.size()
#define FORN(i, n) for(int i = 0; i < n; i++)
#define FORAB(i, a, b) for(int i = a; i <= b; i++)
#define ALL(V) V.begin(), V.end()
#define IN(A, B, C)  ((B) <= (A) && (A) <= (C))
#define AIN(A, B, C) assert(IN(A, B, C))

typedef long long int LL;
//typedef __int128 LLL;
typedef long long LLL;

typedef pair<int, int> PII;
typedef pair<LL, LL> PLL;
typedef pair<LL, int> PLI;
typedef pair<double, double> PDD;
typedef vector<int> VI;
typedef vector<LL> VL;
typedef vector<PLL> VPL;
typedef vector<PII> VP;
typedef vector<double> VD;
typedef vector<vector<int>> VVI;
typedef vector<string> VS;
typedef long double ld;
typedef unsigned long long ULL;

//#define MAXN 1000
//#define MAXN2 MAXN*MAXN
#define MAXN 100

//const LL MOD[2] = { 87420317, 1000000007 };
const LL MOD = 1000000007;
//const LL MOD = 998244353;
//const LL MOD = 547892069;
//const LL INF = 2000000000000000001LL; //2e18 + 1

int A[500003];
int n, k;
int preSmall[500003], sufBig[500003];

/*void Check(VI V) {
	assert(V.back() != n);
	V.push_back(n);

	int last = 0;
	int prev = 0;
	for (int i = 0; i < SZ(V); i++) {
		int v = V[i];
		int cur = 2000000000;
		for (int j = last + 1; j <= v; j++) {
			if (A[j] <= prev) continue;
			cur = MIN(cur, A[j]);
		}
		if (cur == 2000000000) {
			return;
		}
		last = v;
		prev = cur;
	}
	assert(0);
}*/

void solve(int ks) {
	scanf("%d %d", &n, &k);
	for (int i = 1; i <= n; i++) scanf("%d", &A[i]);
	preSmall[1] = A[1];
	for (int i = 2; i <= n; i++) {
		preSmall[i] = MIN(preSmall[i - 1], A[i]);
	}
	sufBig[n] = A[n];
	for (int i = n; i >= 1; i--) {
		sufBig[i] = MAX(sufBig[i + 1], A[i]);
	}

	int strictInc = 1;
	for (int i = 2; i <= n; i++) if (A[i - 1] >= A[i]) strictInc = 0;

	if (strictInc) {
		printf("NIE\n");
		return;
	}

	if (k == 2) {
		for (int i = 1; i < n; i++) {
			if (preSmall[i] >= sufBig[i + 1]) {
				printf("TAK\n");
				//Check({ i });
				printf("%d\n", i);
				return;
			}
		}
		printf("NIE\n");
		return;
	}

	if (k == 3) {
		for (int i = 2; i < n; i++) {
			if (preSmall[i - 1] < A[i] && A[i] < sufBig[i + 1]);
			else {
				printf("TAK\n");
				//Check({ i - 1, i });
				printf("%d %d\n", i - 1, i);
				return;
			}
		}
		printf("NIE\n");
		return;
	}

	int x = 1;
	for (int i = 1; i < n; i++) {
		if (A[i] >= A[i + 1]) {
			x = i;
			break;
		}
	}

	int req_break = k - 1 - (x + 1 != n);
	VI V = { x };
	if (x + 1 != n) V.push_back(x + 1);
	for (int i = 1; i < n; i++) {
		if (i == x) V.push_back(x);
		else if (i == x + 1) V.push_back(x);
		else if (req_break) {
			req_break--;
			V.push_back(i);
		}
	}
	printf("TAK\n");
	//Check(V);
	printf("%d\n", SZ(V));
	for (int i : V) printf("%d ", i);
	printf("\n");
}

void gen() {
}

int main()
{
	double start_time = clock();
#ifdef LOCAL
	freopen("C:\\Home\\Contests\\F\\sample.in", "r", stdin);
	//freopen("C:\\Home\\Contests\\F\\0.out", "w", stdout);
#endif

	gen();

	if (0) {
		int T;
		scanf("%d", &T);
		//AIN(T, 1, 10);
		for (int ks = 1; ks <= T; ks++) {
			solve(ks);
			//if (ks % 1 == 0) fprintf(stderr, "%d done\n", ks);
		}
	}
	else {
		solve(1);
	}

	double end_time = clock();
	fprintf(stderr, "Time = %lf\n", (end_time - start_time) / CLOCKS_PER_SEC);
	return 0;
}