// Marcin Knapik #pragma GCC optimize ("O3") #include<bits/stdc++.h> using namespace std; #define FOR(i, n) for (int i = 0; i < n; i++) #define f first #define s second #define pb push_back #define all(s) s.begin(), s.end() #define sz(s) (int)s.size() using ll = long long; using vi = vector<int>; using vvi = vector<vi>; template <class T>ostream &operator<<(ostream &os, vector<T> &vec){for (T &el : vec){os << el << ' ';}return os;} template <class T>istream &operator>>(istream &is, vector<T> &vec) {for (T &el : vec){is >> el;}return is;} template <class T, class G> ostream &operator<<(ostream &os, pair<T, G> para) { os << para.f << ' ' << para.s; return os;} using ll = long long; using vi = vector<int>; using ii = pair<int, int>; using pll = pair<ll, ll>; using vpll = vector<pll>; using vvpll = vector<vpll>; using vii = vector<ii>; using mp = map<vector<string>, long double>; int n, m; using ld = long double; ld sil(int x){ ld ret = 1.0; for(int i = 2; i <= x; i++){ ret = ret * i; } return ret; } ld choose(ll a, ll b){ return sil(a) / sil(b) / sil(a - b); } bool parzystosc(vector<string> mapa){ bool ret = false; FOR(i, n){ FOR(j, m){ if(mapa[i][j] == 'O'){ ret ^= (i + j) % 2; } } } return ret; } int liczba_ruchow(vector<string> mapa){ int ret = 0; FOR(i, n){ FOR(j, m - 1){ ret += ((mapa[i][j] == '.') ^ (mapa[i][j + 1] == '.')); } } FOR(i, n - 1){ FOR(j, m){ ret += ((mapa[i][j] == '.') ^ (mapa[i + 1][j] == '.')); } } return ret; } void solve () { cin >> n >> m; vector<string> start(n), koniec(n); FOR(i, n){ cin >> start[i]; } FOR(i, n){ cin >> koniec[i]; } cout << setprecision(15) << fixed; if(parzystosc(start) != parzystosc(koniec)){ cout << 0.0 << "\n"; return; } int ruchy = liczba_ruchow(koniec); int pionki = 0; for(auto & u : start){ for(auto & v : u){ pionki += v == 'O'; } } long double ppb = 1.0 / (((n * (m - 1)) + (m * (n - 1))) * choose(n * m - 2, pionki - 1)); cout << ppb * ruchy << '\n'; } int main () { ios::sync_with_stdio(0); cin.tie(0); int tests = 1; // cin >> tests; for (int test = 1; test <= tests; test++) { solve(); } return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 | // Marcin Knapik #pragma GCC optimize ("O3") #include<bits/stdc++.h> using namespace std; #define FOR(i, n) for (int i = 0; i < n; i++) #define f first #define s second #define pb push_back #define all(s) s.begin(), s.end() #define sz(s) (int)s.size() using ll = long long; using vi = vector<int>; using vvi = vector<vi>; template <class T>ostream &operator<<(ostream &os, vector<T> &vec){for (T &el : vec){os << el << ' ';}return os;} template <class T>istream &operator>>(istream &is, vector<T> &vec) {for (T &el : vec){is >> el;}return is;} template <class T, class G> ostream &operator<<(ostream &os, pair<T, G> para) { os << para.f << ' ' << para.s; return os;} using ll = long long; using vi = vector<int>; using ii = pair<int, int>; using pll = pair<ll, ll>; using vpll = vector<pll>; using vvpll = vector<vpll>; using vii = vector<ii>; using mp = map<vector<string>, long double>; int n, m; using ld = long double; ld sil(int x){ ld ret = 1.0; for(int i = 2; i <= x; i++){ ret = ret * i; } return ret; } ld choose(ll a, ll b){ return sil(a) / sil(b) / sil(a - b); } bool parzystosc(vector<string> mapa){ bool ret = false; FOR(i, n){ FOR(j, m){ if(mapa[i][j] == 'O'){ ret ^= (i + j) % 2; } } } return ret; } int liczba_ruchow(vector<string> mapa){ int ret = 0; FOR(i, n){ FOR(j, m - 1){ ret += ((mapa[i][j] == '.') ^ (mapa[i][j + 1] == '.')); } } FOR(i, n - 1){ FOR(j, m){ ret += ((mapa[i][j] == '.') ^ (mapa[i + 1][j] == '.')); } } return ret; } void solve () { cin >> n >> m; vector<string> start(n), koniec(n); FOR(i, n){ cin >> start[i]; } FOR(i, n){ cin >> koniec[i]; } cout << setprecision(15) << fixed; if(parzystosc(start) != parzystosc(koniec)){ cout << 0.0 << "\n"; return; } int ruchy = liczba_ruchow(koniec); int pionki = 0; for(auto & u : start){ for(auto & v : u){ pionki += v == 'O'; } } long double ppb = 1.0 / (((n * (m - 1)) + (m * (n - 1))) * choose(n * m - 2, pionki - 1)); cout << ppb * ruchy << '\n'; } int main () { ios::sync_with_stdio(0); cin.tie(0); int tests = 1; // cin >> tests; for (int test = 1; test <= tests; test++) { solve(); } return 0; } |