#include <bits/stdc++.h> using namespace std; #define ll long long #define rng(i,a,b) for(int i=int(a);i<int(b);i++) #define rep(i,b) rng(i,0,b) typedef vector<int> vi; typedef vector<vi> vvi; typedef vector<vvi> vvvi; typedef vector<ll> vl; typedef vector<vl> vvl; typedef vector<vvl> vvvl; typedef pair<int,int> ii; template<class t> using vc=vector<t>; template<class t> using vvc=vc<vc<t>>; const int MOD = 998244353; ll read(){ ll i; cin>>i; return i; } vi readvi(int n,int off=0,int shift=0){ vi v(n+shift); rep(i,shift)v[i]=0; rep(i,n)v[i+shift]=read()+off; return v; } void YesNo(bool condition, bool do_exit=true) { if (condition) cout << "Yes" << endl; else cout << "No" << endl; if (do_exit) exit(0); } int main(void ) { ios::sync_with_stdio(false); cin.tie(NULL); int n,k; cin >> n >> k; string s; cin >> s; vi pref_ends(n); vvi num_begins(n, vi(n,0)); // num_begins[l][r] = num of begins at l which end at r. vvi begins_at_level(n); int balance=0; rep(i,n) { if (i>0) pref_ends[i] = pref_ends[i-1]; else pref_ends[i]=0; if (s[i] == ')') { begins_at_level[balance].resize(0); if (balance > 0) { --balance; for (auto b : begins_at_level[balance]) num_begins[b][i]++; pref_ends[i] += begins_at_level[balance].size(); } } if (s[i] == '(') { begins_at_level[balance].push_back(i); ++balance; } } vvi pref_begins(n, vi(n,0)); // pref_begins[l][r] = num of begins at l which end at <=r. rep(l,n) rep(r,n) pref_begins[l][r] = num_begins[l][r] + (r > 0 ? pref_begins[l][r-1] : 0); vvi pref_pref_begins(n, vi(n,0)); // pref_pref_begins[l][r] = num of begins at <=l which end at <=r. rep(l,n) rep(r,n) pref_pref_begins[l][r] = pref_begins[l][r] + (l > 0 ? pref_pref_begins[l-1][r] : 0); vvi dp(n,vi(k,0)); //dp[i][j] == suma nawiasowosci w s[:i] z j separatorami (j+1 częściami) rng(i,1,n) { dp[i][0] = pref_ends[i]; rng(j,1,min(i,k)) { dp[i][j] = INT_MAX; rep(t, i) { dp[i][j] = min(dp[i][j], dp[t][j - 1] + pref_ends[i] - pref_pref_begins[t][i]); } } } cout << dp[n-1][k-1] << endl; return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 | #include <bits/stdc++.h> using namespace std; #define ll long long #define rng(i,a,b) for(int i=int(a);i<int(b);i++) #define rep(i,b) rng(i,0,b) typedef vector<int> vi; typedef vector<vi> vvi; typedef vector<vvi> vvvi; typedef vector<ll> vl; typedef vector<vl> vvl; typedef vector<vvl> vvvl; typedef pair<int,int> ii; template<class t> using vc=vector<t>; template<class t> using vvc=vc<vc<t>>; const int MOD = 998244353; ll read(){ ll i; cin>>i; return i; } vi readvi(int n,int off=0,int shift=0){ vi v(n+shift); rep(i,shift)v[i]=0; rep(i,n)v[i+shift]=read()+off; return v; } void YesNo(bool condition, bool do_exit=true) { if (condition) cout << "Yes" << endl; else cout << "No" << endl; if (do_exit) exit(0); } int main(void ) { ios::sync_with_stdio(false); cin.tie(NULL); int n,k; cin >> n >> k; string s; cin >> s; vi pref_ends(n); vvi num_begins(n, vi(n,0)); // num_begins[l][r] = num of begins at l which end at r. vvi begins_at_level(n); int balance=0; rep(i,n) { if (i>0) pref_ends[i] = pref_ends[i-1]; else pref_ends[i]=0; if (s[i] == ')') { begins_at_level[balance].resize(0); if (balance > 0) { --balance; for (auto b : begins_at_level[balance]) num_begins[b][i]++; pref_ends[i] += begins_at_level[balance].size(); } } if (s[i] == '(') { begins_at_level[balance].push_back(i); ++balance; } } vvi pref_begins(n, vi(n,0)); // pref_begins[l][r] = num of begins at l which end at <=r. rep(l,n) rep(r,n) pref_begins[l][r] = num_begins[l][r] + (r > 0 ? pref_begins[l][r-1] : 0); vvi pref_pref_begins(n, vi(n,0)); // pref_pref_begins[l][r] = num of begins at <=l which end at <=r. rep(l,n) rep(r,n) pref_pref_begins[l][r] = pref_begins[l][r] + (l > 0 ? pref_pref_begins[l-1][r] : 0); vvi dp(n,vi(k,0)); //dp[i][j] == suma nawiasowosci w s[:i] z j separatorami (j+1 częściami) rng(i,1,n) { dp[i][0] = pref_ends[i]; rng(j,1,min(i,k)) { dp[i][j] = INT_MAX; rep(t, i) { dp[i][j] = min(dp[i][j], dp[t][j - 1] + pref_ends[i] - pref_pref_begins[t][i]); } } } cout << dp[n-1][k-1] << endl; return 0; } |