//Tadrion #include <cstdio> #include <vector> #include <iostream> #include <deque> #include <map> #include <set> #include <string> #include <cstring> #include <cstdlib> #include <cmath> #include <queue> #include <stack> #include <algorithm> #include <utility> using namespace std; #define MAX(a,b) ((a) > (b) ? (a) : (b)) #define MIN(a,b) ((a) < (b) ? (a) : (b)) #define CLEAR(x) (memset(x,0,sizeof(x))) #define SZ(x) ((int)(x).size()) #define ALL(x) (x).begin(),(x).end() #define VAR(v, n) __typeof(n) v = (n) #define FOR(x, b, e) for(int x = b; x <= (e); ++x) #define FORD(x, b, e) for(int x = b; x >= (e); --x) #define REP(x, n) for(int x = 0; x < (n); ++x) #define FOREACH(i, c) for(VAR(i,(c).begin()); i != (c).end(); ++i) #define DBG(v) cout<<#v<<" = "<<v<<endl; #define IN(x,y) ((y).find(x)!=(y).end()) #define ST first #define ND second #define PB push_back #define PF push_front #define MP make_pair typedef long long int LL; typedef pair<int,int> PII; typedef vector<int> VI; int n,m; vector<pair<int, PII> > v; int a,b,c; vector<PII> na,poza; int maxx = 0; int main() { scanf("%d %d",&n,&m); FOR(i,1,n) { scanf("%d %d %d",&a,&b,&c); maxx = MAX(maxx,b); v.PB(MP(a,MP(b-a-c,c))); } sort(v.begin(),v.end()); int cur = 0; /* while(cur < SZ(v) && v[cur].ST == 0) { ac.PB(v[cur].ND); cur++; } */ //sort(ac.begin(),ac.end()); int ok =1; int time = 0; do { vector<PII> q; while(cur < SZ(v) && v[cur].ST == time) { q.PB(v[cur].ND); cur++; } vector<PII> r(SZ(q)+SZ(na)); vector<PII> r2(SZ(poza)+SZ(q)+SZ(na)); std::merge(q.begin(),q.end(),na.begin(),na.end(),r.begin()); std::merge(poza.begin(),poza.end(),r.begin(),r.end(),r2.begin()); na.clear(); poza.clear(); REP(i,SZ(r2)) if(SZ(na) < m){ if(r2[i].ND > 0) na.PB(MP(r2[i].ST,r2[i].ND-1)); } else { if(r2[i].ST > 0) poza.PB(MP(r2[i].ST-1,r2[i].ND)); else { ok=0; goto DAVIE; } } time++; }while(SZ(na) > 0 || cur < SZ(v)); DAVIE: if(ok) printf("TAK\n"); else printf("NIE\n"); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 | //Tadrion #include <cstdio> #include <vector> #include <iostream> #include <deque> #include <map> #include <set> #include <string> #include <cstring> #include <cstdlib> #include <cmath> #include <queue> #include <stack> #include <algorithm> #include <utility> using namespace std; #define MAX(a,b) ((a) > (b) ? (a) : (b)) #define MIN(a,b) ((a) < (b) ? (a) : (b)) #define CLEAR(x) (memset(x,0,sizeof(x))) #define SZ(x) ((int)(x).size()) #define ALL(x) (x).begin(),(x).end() #define VAR(v, n) __typeof(n) v = (n) #define FOR(x, b, e) for(int x = b; x <= (e); ++x) #define FORD(x, b, e) for(int x = b; x >= (e); --x) #define REP(x, n) for(int x = 0; x < (n); ++x) #define FOREACH(i, c) for(VAR(i,(c).begin()); i != (c).end(); ++i) #define DBG(v) cout<<#v<<" = "<<v<<endl; #define IN(x,y) ((y).find(x)!=(y).end()) #define ST first #define ND second #define PB push_back #define PF push_front #define MP make_pair typedef long long int LL; typedef pair<int,int> PII; typedef vector<int> VI; int n,m; vector<pair<int, PII> > v; int a,b,c; vector<PII> na,poza; int maxx = 0; int main() { scanf("%d %d",&n,&m); FOR(i,1,n) { scanf("%d %d %d",&a,&b,&c); maxx = MAX(maxx,b); v.PB(MP(a,MP(b-a-c,c))); } sort(v.begin(),v.end()); int cur = 0; /* while(cur < SZ(v) && v[cur].ST == 0) { ac.PB(v[cur].ND); cur++; } */ //sort(ac.begin(),ac.end()); int ok =1; int time = 0; do { vector<PII> q; while(cur < SZ(v) && v[cur].ST == time) { q.PB(v[cur].ND); cur++; } vector<PII> r(SZ(q)+SZ(na)); vector<PII> r2(SZ(poza)+SZ(q)+SZ(na)); std::merge(q.begin(),q.end(),na.begin(),na.end(),r.begin()); std::merge(poza.begin(),poza.end(),r.begin(),r.end(),r2.begin()); na.clear(); poza.clear(); REP(i,SZ(r2)) if(SZ(na) < m){ if(r2[i].ND > 0) na.PB(MP(r2[i].ST,r2[i].ND-1)); } else { if(r2[i].ST > 0) poza.PB(MP(r2[i].ST-1,r2[i].ND)); else { ok=0; goto DAVIE; } } time++; }while(SZ(na) > 0 || cur < SZ(v)); DAVIE: if(ok) printf("TAK\n"); else printf("NIE\n"); return 0; } |