#include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <vector> #include <set> #include <map> #include <cmath> #include <list> #include <ctime> #include <sstream> #include <queue> #include <stack> #include <bitset> #include <unordered_set> #include <unordered_map> using namespace std; typedef vector<int> vi; typedef pair<int,int> pii; typedef long long ll; typedef short int sint; #define FOR(x, b, e) for(int x=(b); x<=(e); ++x) #define FORD(x, b, e) for(int x=((int)(b))-1; x>=(e); --x) #define REP(x, n) for(int x=0; x<(n); ++x) #define ALL(c) c.begin(),c.end() #define SIZE(x) ((int)((x).size())) #define PB push_back #define ST first #define ND second #define mp(x,y) make_pair(x,y) #define DEBUG 1 #define debug(x) {if (DEBUG)cerr <<#x <<" = " <<x <<endl; } #define debugv(x) {if (DEBUG) {cerr <<#x <<" = "; FOREACH(it, (x)) cerr <<*it <<", "; cout <<endl; }} #define REMAX(a,b) (a)=max((a),(b)); #define REMIN(a,b) (a)=min((a),(b)); #define wez(n) int (n); scanf("%d",&(n)); #define wez2(n,m) int (n),(m); scanf("%d %d",&(n),&(m)); const int N = 301; vi za[N]; int maxD[N]; int pre[N]; bool del[N]; int n, m, k; int solve(int kp) { FOR(i, 1, n) if (!del[i]) {maxD[i] = 1; } else {maxD[i] = 0;} int najw = -1, maxDist = 0; FOR(i, 1, n) { if (del[i]) { // this element is deleted continue; } if (maxD[i] > maxDist) { najw = i; maxDist = maxD[i]; } for (auto x : za[i]) { if (!del[x] && maxD[i] + 1 > maxD[x]) { pre[x] = i; maxD[x] = maxD[i] + 1; } } } if (kp == 0) { // if (maxDist < 11) { // printf("%d for: ", maxDist); for (auto de : del) printf("%d ", de); printf("\n"); // } return maxDist; } // printf("max dist: %d\n", maxDist); vi kand; REP(i, maxDist) { kand.PB(najw); najw = pre[najw]; } int nRes = N; for (auto kandydat : kand) { del[kandydat] = true; int res = solve(kp - 1); nRes = min(nRes, res); del[kandydat] = false; } return nRes; } int main() { scanf("%d %d %d", &n, &m, &k); REP(i, m) { int x, y; scanf("%d %d", &x, &y); za[x].PB(y); } int res = solve(k); printf("%d\n", res); return 0; }
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 | #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <vector> #include <set> #include <map> #include <cmath> #include <list> #include <ctime> #include <sstream> #include <queue> #include <stack> #include <bitset> #include <unordered_set> #include <unordered_map> using namespace std; typedef vector<int> vi; typedef pair<int,int> pii; typedef long long ll; typedef short int sint; #define FOR(x, b, e) for(int x=(b); x<=(e); ++x) #define FORD(x, b, e) for(int x=((int)(b))-1; x>=(e); --x) #define REP(x, n) for(int x=0; x<(n); ++x) #define ALL(c) c.begin(),c.end() #define SIZE(x) ((int)((x).size())) #define PB push_back #define ST first #define ND second #define mp(x,y) make_pair(x,y) #define DEBUG 1 #define debug(x) {if (DEBUG)cerr <<#x <<" = " <<x <<endl; } #define debugv(x) {if (DEBUG) {cerr <<#x <<" = "; FOREACH(it, (x)) cerr <<*it <<", "; cout <<endl; }} #define REMAX(a,b) (a)=max((a),(b)); #define REMIN(a,b) (a)=min((a),(b)); #define wez(n) int (n); scanf("%d",&(n)); #define wez2(n,m) int (n),(m); scanf("%d %d",&(n),&(m)); const int N = 301; vi za[N]; int maxD[N]; int pre[N]; bool del[N]; int n, m, k; int solve(int kp) { FOR(i, 1, n) if (!del[i]) {maxD[i] = 1; } else {maxD[i] = 0;} int najw = -1, maxDist = 0; FOR(i, 1, n) { if (del[i]) { // this element is deleted continue; } if (maxD[i] > maxDist) { najw = i; maxDist = maxD[i]; } for (auto x : za[i]) { if (!del[x] && maxD[i] + 1 > maxD[x]) { pre[x] = i; maxD[x] = maxD[i] + 1; } } } if (kp == 0) { // if (maxDist < 11) { // printf("%d for: ", maxDist); for (auto de : del) printf("%d ", de); printf("\n"); // } return maxDist; } // printf("max dist: %d\n", maxDist); vi kand; REP(i, maxDist) { kand.PB(najw); najw = pre[najw]; } int nRes = N; for (auto kandydat : kand) { del[kandydat] = true; int res = solve(kp - 1); nRes = min(nRes, res); del[kandydat] = false; } return nRes; } int main() { scanf("%d %d %d", &n, &m, &k); REP(i, m) { int x, y; scanf("%d %d", &x, &y); za[x].PB(y); } int res = solve(k); printf("%d\n", res); return 0; } |