// C program to Count
// Inversions in an array
// using Merge Sort
#include <bits/stdc++.h>
#include <cstdio>
#include <vector>
#include "teatr.h"
#include "message.h"
#include <cmath>
unsigned long long int _mergeSort(int arr[], int temp[], int left, int right);
unsigned long long int merge(int arr[], int temp[], int left, int mid, int right);
/* This function sorts the input array and returns the
number of inversions in the array */
unsigned long long int mergeSort(int arr[], int array_size)
{
int* temp = (int*)malloc(sizeof(int) * array_size);
return _mergeSort(arr, temp, 0, array_size - 1);
}
/* An auxiliary recursive function that sorts the input array and
returns the number of inversions in the array. */
unsigned long long int _mergeSort(int arr[], int temp[], int left, int right)
{
int mid;
unsigned long long int inv_count = 0;
if (right > left) {
/* Divide the array into two parts and call _mergeSortAndCountInv()
for each of the parts */
mid = (right + left) / 2;
/* Inversion count will be sum of inversions in left-part, right-part
and number of inversions in merging */
inv_count = _mergeSort(arr, temp, left, mid);
inv_count += _mergeSort(arr, temp, mid + 1, right);
/*Merge the two parts*/
inv_count += merge(arr, temp, left, mid + 1, right);
}
return inv_count;
}
/* This funt merges two sorted arrays and returns inversion count in
the arrays.*/
unsigned long long int merge(int arr[], int temp[], int left, int mid, int right)
{
int i, j, k;
unsigned long long int inv_count = 0;
i = left; /* i is index for left subarray*/
j = mid; /* j is index for right subarray*/
k = left; /* k is index for resultant merged subarray*/
while ((i <= mid - 1) && (j <= right)) {
if (arr[i] <= arr[j]) {
temp[k++] = arr[i++];
}
else {
temp[k++] = arr[j++];
/*this is tricky -- see above explanation/diagram for merge()*/
inv_count = inv_count + (mid - i);
}
}
/* Copy the remaining elements of left subarray
(if there are any) to temp*/
while (i <= mid - 1)
temp[k++] = arr[i++];
/* Copy the remaining elements of right subarray
(if there are any) to temp*/
while (j <= right)
temp[k++] = arr[j++];
/*Copy back the merged elements to original array*/
for (i = left; i <= right; i++)
arr[i] = temp[i];
return inv_count;
}
int widownia[1000000];
/* Driver program to test above functions */
int main(int argv, char** args)
{
int n;
if(MyNodeId()==0)
{
n=GetN();
for(int i=0;i<n;i++)
{
widownia[i]=GetElement(i);
}
printf("%llu\n", mergeSort(widownia, n));
return 0;
}
return 0;
}
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 | // C program to Count // Inversions in an array // using Merge Sort #include <bits/stdc++.h> #include <cstdio> #include <vector> #include "teatr.h" #include "message.h" #include <cmath> unsigned long long int _mergeSort(int arr[], int temp[], int left, int right); unsigned long long int merge(int arr[], int temp[], int left, int mid, int right); /* This function sorts the input array and returns the number of inversions in the array */ unsigned long long int mergeSort(int arr[], int array_size) { int* temp = (int*)malloc(sizeof(int) * array_size); return _mergeSort(arr, temp, 0, array_size - 1); } /* An auxiliary recursive function that sorts the input array and returns the number of inversions in the array. */ unsigned long long int _mergeSort(int arr[], int temp[], int left, int right) { int mid; unsigned long long int inv_count = 0; if (right > left) { /* Divide the array into two parts and call _mergeSortAndCountInv() for each of the parts */ mid = (right + left) / 2; /* Inversion count will be sum of inversions in left-part, right-part and number of inversions in merging */ inv_count = _mergeSort(arr, temp, left, mid); inv_count += _mergeSort(arr, temp, mid + 1, right); /*Merge the two parts*/ inv_count += merge(arr, temp, left, mid + 1, right); } return inv_count; } /* This funt merges two sorted arrays and returns inversion count in the arrays.*/ unsigned long long int merge(int arr[], int temp[], int left, int mid, int right) { int i, j, k; unsigned long long int inv_count = 0; i = left; /* i is index for left subarray*/ j = mid; /* j is index for right subarray*/ k = left; /* k is index for resultant merged subarray*/ while ((i <= mid - 1) && (j <= right)) { if (arr[i] <= arr[j]) { temp[k++] = arr[i++]; } else { temp[k++] = arr[j++]; /*this is tricky -- see above explanation/diagram for merge()*/ inv_count = inv_count + (mid - i); } } /* Copy the remaining elements of left subarray (if there are any) to temp*/ while (i <= mid - 1) temp[k++] = arr[i++]; /* Copy the remaining elements of right subarray (if there are any) to temp*/ while (j <= right) temp[k++] = arr[j++]; /*Copy back the merged elements to original array*/ for (i = left; i <= right; i++) arr[i] = temp[i]; return inv_count; } int widownia[1000000]; /* Driver program to test above functions */ int main(int argv, char** args) { int n; if(MyNodeId()==0) { n=GetN(); for(int i=0;i<n;i++) { widownia[i]=GetElement(i); } printf("%llu\n", mergeSort(widownia, n)); return 0; } return 0; } |
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